从vb.net调用存储过程时,如果连接字符串中未指定超时,则会有默认的SQL超时时间吗?我不确定CommandTimeout连接字符串中是否有指定但是我正在浏览所有可能性.
示例如果在30秒(或更多)之后没有结果抛出:
`System.Data.SqlClient.SqlException: Timeout expired. The timeout period elapsed prior to completion of the operation or the server is not responding.`
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SQL事件探查器说,当程序超时时,脚本会在30秒内运行并结束.
该脚本在SQL Server中自行运行大约1分45秒.
在尝试优化SQL脚本时,我建议添加索引.
指定索引应该包含哪些数据库的最简单方法是什么?
IF EXISTS (SELECT * FROM sysindexes WHERE NAME = 'idx_TableA')
DROP INDEX TableA.idx_TableA
IF EXISTS (SELECT * FROM sysindexes WHERE NAME = 'idx_TableB')
DROP INDEX TableB.idx_TableB
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在上面的代码中,TableA在DB-A中,而TableB在DB-B中.
我收到以下错误,当我改变DROP INDEX TableA.idx_TableA 到DROP INDEX DB-A.dbo.TableA.idx_TableA
Msg 166, Level 15, State 1, Line 2
'DROP INDEX' does not allow specifying the database name as a prefix to the object name.
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任何想法都表示赞赏.
我很奇怪看到我可以制作代码的行数很少.有没有办法将其压缩为内联案例陈述?
switch (FIZZBUZZ)
{
case "Fizz":
{
//Do one process
break;
}
case "Buzz":
{
//Do one process
break;
}
case "FizzBuzz":
{
//Do one process
break;
}
}
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看起来像这样:
switch (FIZZBUZZ)
{
case "Fizz": //Do one process
case "Buzz": //Do one process
case "FizzBuzz": //Do one process
}
Run Code Online (Sandbox Code Playgroud) OnSelectedIndexChanged我的下拉框没有触发该事件.我看过的所有论坛都告诉我添加AutoPostBack="true",但这并没有改变结果.
HTML:
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title></title>
</head>
<body>
<form id="form1" runat="server">
<div>
<asp:Label ID="Label1" runat="server" Text="Current Time: " /><br />
<asp:Label ID="lblCurrent" runat="server" Text="Label" /><br /><br />
<asp:DropDownList ID="cboSelectedLocation" runat="server" AutoPostBack="true" OnSelectedIndexChanged="cboSelectedLocation_SelectedIndexChanged" /><br /><br />
<asp:Label ID="lblSelectedTime" runat="server" Text="Label" />
</div>
</form>
</body>
</html>
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代码背后:
public partial class _Default : Page
{
string _sLocation = string.Empty;
string _sCurrentLoc = string.Empty;
TimeSpan _tsSelectedTime;
protected void Page_Load(object sender, EventArgs e)
{
AddTimeZones();
cboSelectedLocation.Focus();
lblCurrent.Text = "Currently in " …Run Code Online (Sandbox Code Playgroud)