小编rea*_*lli的帖子

我正在使用serde和serde_json 1.0来解码base64字符串中的数据:

fn from_base64_str<T: Deserialize>(string: &str) -> T {
    let slice = decode_config(string, URL_SAFE).unwrap();     
    serde_json::from_slice(&slice).unwrap()
}

当我编译时,我得到了这个:

error[E0106]: missing lifetime specifier
 --> src/main.rs:6:23
  |
6 | fn from_base64_str<T: Deserialize>(string: &str) -> T {
  |                       ^^^^^^^^^^^ expected lifetime parameter

检查serde doc,Deserialize定义为:

pub trait Deserialize<'de>: Sized {

所以我添加了生命周期:

fn from_base64_str<'de, T: Deserialize<'de>>(string: &str) -> T {
    let slice = decode_config(string, URL_SAFE).unwrap();     
    serde_json::from_slice(&slice).unwrap()
}

然后编译器告诉我:

error: `slice` does not live long enough
  --> src/main.rs:11:29
   |
11 |     serde_json::from_slice(&slice).unwrap()
   |                             ^^^^^ does …

最近,我试图解决Haskell 99问题,第66次(紧凑地布置树).我成功了,但对这里的解决方案感到困惑(http://www.haskell.org/haskellwiki/99_questions/Solutions/66).

layout :: Tree a -> Tree (a, Pos)
layout t = t'
  where (l, t', r) = layoutAux x1 1 t
    x1 = maximum l + 1

    layoutAux :: Int -> Int -> Tree a -> ([Int], Tree (a, Pos), [Int])
    layoutAux x y Empty = ([], Empty, [])
    layoutAux x y (Branch a l r) = (ll', Branch (a, (x,y)) l' r', rr')
      where (ll, l', lr) = layoutAux (x-sep) (y+1) l
            (rl, r', rr) …