小编Ben*_*kin的帖子

我试图找到awk一个类的第二列数据的平均值.这是我当前的代码,我的讲师提供了框架:

#!/bin/awk

### This script currently prints the total number of rows processed.
### You must edit this script to print the average of the 2nd column
### instead of the number of rows.

# This block of code is executed for each line in the file
{
x=sum
read name
        awk 'BEGIN{sum+=$2}'
        # The script should NOT print out a value for each line
}
# The END block is processed after the last line is read …

我正在尝试用 C 语言为一个类构建一个非常简单的解析器。它所要做的就是从输入文件中读取标志，确定该标志是否位于 int、char 或 float 之前，然后将 int/float/char 写入相应的 .txt 文件。例如 I 9898 将被打印到 int.txt。每当使用讲师提供的测试脚本时，我都会收到以下错误：

parser.c:1:1: error: unknown type name \xe2\x80\x98e\xe2\x80\x99\nparser.c:1:10: error: expected \xe2\x80\x98=\xe2\x80\x99, \xe2\x80\x98,\xe2\x80\x99, \xe2\x80\x98;\xe2\x80\x99, \xe2\x80\x98asm\xe2\x80\x99 or \xe2\x80\x98__attribute__\xe2\x80\x99 before \xe2\x80\x98on\xe2\x80\x99\nparser.c:1:10: error: unknown type name \xe2\x80\x98on\xe2\x80\x99

这是我的代码，请告诉我。非常感谢：

int main(int argc, char *argv[])\n{\n#include <stdio.h>\n    FILE *input = fopen("input.txt", "r");\n    FILE *ints.txt = fopen("ints.txt" "w");\n    FILE *chars.txt = fopen("chars.txt", "w");\n    FILE *floats.txt = fopen("floats.txt", "w");\n\n    char flag;\n    int ipint;\n    char ipchar;\n    float ipfloat;\n    int exitStatus = fscanf(input.txt, "%c", &flag);\n\n …