小编Ken*_*Ken的帖子

我有一个SELECT语句是从一个CASE WHEN THEN状态(或者可以使用多个IF语句)别名为'Length'计算的,我需要正确地将结果组合在一起.SELECT似乎正在工作,但该组将它们分组错误.这是我的发言:

SELECT CASE 
    WHEN DATEDIFF(o.EndDate, o.StartDate) < 30 THEN '<1 Month'
    WHEN DATEDIFF(o.EndDate, o.StartDate) < 90 THEN '1 - 2 Months'
    WHEN DATEDIFF(o.EndDate, o.StartDate) < 210 THEN '3 - 4 Months'
    ELSE '>4 Months' END AS 'Length', 
    COUNT(DISTINCT(person.ID)) AS 'COUNT'
FROM person
    INNER JOIN opportunity AS o
    INNER JOIN Organization AS org
    ON person.EntityID = o.id 
        AND O.OrganizationID = Org.ID
WHERE person.TitleID = 2
    AND o.bID = 1
GROUP BY 'Length'
ORDER BY 'Length' ASC;

这将所有结果分组为'3 - 4个月',这是不对的..

我正在尝试使用下面的CASE子句将2行结果合并为1.'<26'应该只出现一次,结果应该合并.

SELECT  
    CASE org.size
        WHEN 0 THEN '<26'
        WHEN 1 THEN '<26'
        WHEN 2 THEN '26-50'
        WHEN 3 THEN '51-100'
        WHEN 4 THEN '101-250'
        WHEN 5 THEN '251-500'
        WHEN 6 THEN '501-1000'
        WHEN 7 THEN '1001-5000'
        ELSE '5000+' END
        AS 'Size',
        COUNT(DISTINCT org.id) AS '# of Companies'
FROM org INNER JOIN usr ON usr.orgid = org.id
    INNER JOIN usr_role ON usr.id = usr_role.usrid
WHERE org.deleted = 0 AND usr.brnd = 1 AND usr_role.role = 1
GROUP BY org.size;

我读过这篇文章:http://www.xaprb.com/blog/2006/12/07/how-to-select-the-firstleastmax-row-per-group-in-sql/并搜索其他问题

我有一个表格,如:

| table.id    | USER.id
----------------------------------------------
| 1           | 101
| 2           | 101
| 3           | 101
| 4           | 101 
| 5           | 101
| 6           | 101
| 7           | 101 
| 8           | 101
| 9           | 101 
| 10          | 101
| 11          | 102
| 12          | 102 
| 13          | 102
| 14          | 102
| 15          | 103 
| 16          | 103
| 17          | 103
| …

编写此查询的正确方法是什么？我的customers表中有一个名为TimeStamp的列.我在2012年尝试找到创建帐户的客户时遇到错误.我尝试过:

SELECT 'TimeStamp' AS CreatedDate
FROM customers
WHERE 'CreatedDate' >= '2012-01-01' AND 'CreatedDate' <= '2012-12-31'

并且

SELECT *
FROM customers
WHERE 'TimeStamp' >= '2012-01-01' AND 'TimeStamp' <= '2012-12-31'

并且总是没有结果(应该有数千)

在Google表格中，我试图编写一个查询（不是独立的数据透视表或脚本），它根据基于if/then语句的计算值进行分组。

这是我的示例数据：

Name    Days
Bob     0
Ed      1
Frank   2
Joey    4
Deluth  7
Henry   12

按 B 列分组相当简单：

=QUERY(A1:B7,"SELECT B, COUNT(B) GROUP BY B")

其输出：

Days    count
0       1
1       1
2       1
4       1
7       1
12      1

但我想做的是将这些日子分组到特定的桶中。存储桶和所需的输出将是所需的输出：

Days    count
0       1
1       1
2-5     2
6-9     1
10+     1

所以它几乎是“如果 0 那么 '0'，如果 1 那么 '1'，如果 >1 AND <=5 那么 '2-5' 等等，最后有一个 Group By？这将如何写成查询格式？

我正在尝试将2个完全不同的查询的数值结果相除。

最终结果应为查询1除以查询2

查询1 =

SELECT COUNT(DISTINCT(table1.ID)) AS count_1
FROM table1 
    INNER JOIN op 
    INNER JOIN Org 
    ON table1.EID = op.id 
        AND Op.OrgID = Org.ID
WHERE table1.TitleID = 123
    AND op.BrandID = 1 
    AND op.Start <= NOW() AND op.End >= NOW();

查询2 =

SELECT COUNT(DISTINCT user.id) AS count_2
FROM table1 INNER JOIN user INNER JOIN ur
    ON table1.EID = user.id AND ur.userID = user.id
WHERE 
    user.BrandID = 1 
    AND table1.TitleID = 123
    AND ur.role = 0
    AND user.Inactive = 0;

我有一个users存储TIMESTAMP 的表,当他们的帐户被创建时.我正在尝试编写一个查询,该查询将显示在给定时间段内按周(按周一开始)分组的新用户.导演将进入并选择报告日期范围,因此选择2个变量.他们应该看到显示所有在2个选定变量日期之间注册的新用户的结果,按周(周的周一开始)分组

变量: @StartRangeSelectDate @EndRangeSelectDate

用户表:

| id         | TIMESTAMP
----------------------------------------------
| 1          | 2013-09-02
| 2          | 2013-09-08
| 3          | 2013-09-12
| 4          | 2013-09-27

结果应该是(当选择的开始日期类似于2013-09-01,结束日期是2013-09-29:

| YearWeek         | # of New Users
----------------------------------------------
| 2013 36          | 2
| 2013 37          | 1
| 2013 38          | 0
| 2013 39          | 1

查询以显示日期范围中的新用户总数,但尚未在日期范围内按周分组:

SELECT COUNT(user.id) AS '# of New Users in Date Range'
FROM user 
WHERE user.Inactive = 0
    AND user.TimeStamp BETWEEN @StartRangeSelectDate AND …

使用MySql

我有以下变量(以"3"和"2014"为例):

SET @Month = 3;
SET @Year = 2014;

期望的结果

I'd like to get the first day of the month and the last day of the month separately, 
using the variables (avoiding any NOW() or CURDATE() formulas), in %Y-%m-%d format. In other words:

2014-03-01
2014-03-31

我已经尝试了以下基本功能的许多可能性,加上一些我已删除

SELECT LAST_DAY(`SELECT(@Year)-03-01`)
SELECT LAST_DAY('@Year-@Month')
SELECT DATE_FORMAT(?, '%Y-%m-01')