我正在尝试使用我的Android应用程序中的相机开发.
问题是相机总是返回结果代码0,无论我是按完还是取消.我使用的代码片段如下:
protected void startCameraActivity()
{
Log.i("MakeMachine", "startCameraActivity()" );
File file = new File( _path );
Uri outputFileUri = Uri.fromFile( file );
Intent intent = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE);
intent.putExtra( MediaStore.EXTRA_OUTPUT, outputFileUri );
startActivityForResult(intent, 0);
}
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data)
{
Log.i( "MakeMachine", "resultCode: " + resultCode );
switch( resultCode )
{
case 0:
Log.i( "MakeMachine", "User cancelled" );
break;
case -1:
Log.i( "MakeMachine", "User done" );
onPhotoTaken();
break;
}
}
logcat显示:
05-31 14:58:15.367: E/asset(29114): MAS: getAppPckgAndVerCode …我启动了PreferenceActivity,我以编程方式添加了一些首选项屏幕.所以我有一个列表与我的偏好屏幕.
例:
所以我迭代并调用一个函数(Board是一个自定义对象):
private PreferenceScreen CreatePreferenceScreen(Board b) {
PreferenceScreen p = getPreferenceManager().createPreferenceScreen(this);
p.setPersistent(true);
p.setKey("preferenceScreen_" + b.getId());
PreferenceCategory general = new PreferenceCategory(this);
general.setTitle("General");
p.addPreference(general);
Preference delete = new Preference(this);
delete.setTitle("delete");
final PreferenceScreen pFinal = p;
delete.setOnPreferenceClickListener(new Preference.OnPreferenceClickListener() {
@Override
public boolean onPreferenceClick(Preference arg0) {
String delId = board.getId();
PreferenceCategory themes = (PreferenceCategory) findPreference("themes");
PreferenceScreen screen =(PreferenceScreen)findPreference("preferenceScreen_" + delId);
themes.removePreference(screen);
/*GO BACK TO PREFERENCEACTIVITY HERE OR KILL THIS SCREEN*/
return true;
}
});
general.addPreference(delete);
return p;
} …我开发了一个简单的应用程序来计算患2型糖尿病的风险.该应用程序在我的iPhone 3Gs上从xcode运行良好.我将应用程序归档到一个.ipa文件中,然后将应用程序上传到我的testflightapp.com帐户.我已经使用标准的testflightapp.com程序在我的iPhone上安装了该应用程序:点击testflightapp.com电子邮件中的安装链接.
当我运行应用程序时,我会看到启动图像几秒钟然后它就会消失.我的iPhone在xcode中的控制台显示出了什么问题,但我不知道这意味着什么:
Jan 8 20:00:42 unknown com.apple.launchd[1] <Warning>: (UIKitApplication:com.reinvdo.diabete[0xa6a]) Conflict with job: UIKitApplication:com.reinvdo.diabete[0x291b] over Mach service: com.reinvdo.diabete
Jan 8 20:00:42 unknown com.apple.launchd[1] <Warning>: (UIKitApplication:com.reinvdo.diabete[0xa6a]) Conflict with job: UIKitApplication:com.reinvdo.diabete[0x291b] over Mach service: com.reinvdo.diabete.UIKit.migserver
Jan 8 20:00:42 unknown kernel[0] <Debug>: launchd[4255] Builtin profile: container (sandbox)
Jan 8 20:00:42 unknown kernel[0] <Debug>: launchd[4255] Container: /private/var/mobile/Applications/64A83260-5918-4109-A861-A3399D825654 [69] (sandbox)
Jan 8 20:00:42 unknown com.apple.launchd[1] <Warning>: (UIKitApplication:com.reinvdo.diabete[0x291b]) The following job tried to hijack the service "com.reinvdo.diabete" from …在我的应用程序中，我们正在从SecurityContextHolderAuthentication对象捕获每个事务的用户详细信息。
但这UserID似乎是错误的。下面是代码片段供您参考。
SecurityContext.xml
春季安全3.2-
<security:http auto-config="true">
<!-- Restrict URLs based on role -->
<security:headers>
<security:cache-control/>
<security:content-type-options/>
<security:frame-options policy="DENY"/>
<security:xss-protection/>
</security:headers>
<security:intercept-url pattern="/login*" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/logoutSuccess*" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/resources/**" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/web/forgotPwd/**" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/web/**" access="ROLE_USER" />
<security:form-login login-page="/login.html" default-target-url="/web/landing/homePage.html"
always-use-default-target="true" authentication-failure-handler-ref="exceptionTranslationFilter" />
<security:logout delete-cookies="JSESSIONID" invalidate-session="true"
logout-success-url="/logout.html" />
<security:session-management session-fixation-protection="newSession" invalid-session-url="/login.html?login_error=sessionexpired" session-authentication-error-url="/login.html?login_error=alreadyLogin">
<security:concurrency-control max-sessions="1" expired-url="/login.html?login_error=duplicateOrsessionexpired" error-if-maximum-exceeded="false" />
</security:session-management>
<security:csrf />
<security:remember-me token-repository-ref="remembermeTokenRepository" key="myAppKey"/>
</security:http>
<security:authentication-manager alias="authenticationManager">
<security:authentication-provider user-service-ref="userDetailsServiceImpl">
<security:password-encoder ref="passwordEncoder" />
</security:authentication-provider>
</security:authentication-manager> …我已经onTouchEvent()在View课堂上覆盖了这个方法,并试图处理一个EventMotion.ACTION_MOVE.
我使用以下代码:
if (event_.getAction() == MotionEvent.ACTION_MOVE) {
historySize = event_.getHistorySize();
endX = event_.getHistoricalX(historySize-1);
}
我不想讨论这段代码的安全性.
在Android 2.1-update1和Android 2.2.1上它运行良好,但在Android 2.3.1上,它会因ArrayIndexOutOfBounds异常而崩溃.
在Android 2.3.1 getHistorySize()和getHistoricalX()Android 2.3.1中有什么变化？
我是编程新手,正在上课.我的一项任务涉及使用switch语句,这是我们最近才学到的.我得到了大部分代码,但由于某种原因,switch语句不起作用.程序编译并提示必要的输入,但在输入值时不打印任何switch语句.基本上,我想提示用户输入学号(任意号码),输入学分,并打印正确的陈述.这是我的代码:
import java.io.*;
import java.util.*;
public class Prog222
{
public static void main(String[] args)
{
for(int i = 1; i<=4; i++)
{
double freshmanC = 1.0;
double sophomoreC = 2.0;
double juniorC = 3.0;
double seniorC = 4.0;
Scanner kbReader = new Scanner(System.in);
System.out.print("Enter student number "); //Enter 2352, 3639, 4007, and 4915 respectively
int studentNumber = kbReader.nextInt();
System.out.print("Enter credits "); //Enter 30.0, 29.9, 70, and 103.7 respectively
double credits = kbReader.nextDouble();
switch((int) credits)
{
case '1': //Below 30 credit …