我无法理解如何在PHP SOAP调用中传递用户定义的类型.有人可以给我一个提示(或手册的链接)吗?
示例:在我的WSDL文件中,我定义了类型:
<types>
<schema targetNamespace="http://example.com/CustData"
xmlns="http://www.w3.org/2000/10/XMLSchema">
<element name="personalInformation">
<complexType>
<all>
<element name="name" type="xsd:string"/>
<element name="title" type="xsd:string"/>
<element name="lang" type="xsd:string"/>
</all>
</complexType>
</element>
</schema>
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我像这样定义服务响应消息:
<message name='getCustDataResponse'>
<part name='Result' type='xsd:personalInformation'/>
<part name='Result1' type='xsd:string'/>
</message>
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缺少的部分是 - 如何在SOAP服务器端初始化答案?
我试着写:
$arrRes['Result']['name'] = 'xxx';
$arrRes['Result']['title'] = 'yyy';
$arrRes['Result']['lang'] = 'zzz';
$arrRes['Result']['hehehehe1'] = 'test1';
$arrRes['Result']['hehehehe2'] = 'test2';
$arrRes['Result']['hehehehe3'] = 'test3';
$arrRes['Result']['hehehehe4'] = 'test4';
$arrRes['Result1'] = 'result1';
$arrRes['blablabla'] = 'hahaha';
return $arrRes;
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客户端获取响应,当我var_dump它时,它显示arrRes:
array(2) { ["Result"]=> array(7) { ["name"]=> string(3) "xxx" ["title"]=> string(3) "yyy" ["lang"]=> …Run Code Online (Sandbox Code Playgroud)