愚蠢的问题,所以如果答案显而易见,我会道歉但是如何在iterm2上向上滚动以获得完整输出?有时候,例如,如果我正在进行单元测试,那么错误是如此之大,以至于我不能再向上滚动,我不能再向上滚动,但输出继续超出滚动的顶部.我该如何访问?我尝试了更多的页面,但没有让我到那里.
谢谢!
我正在使用Postgres的json数据类型,但想要使用嵌套在json中的数据进行查询/排序.
我想在json数据类型上使用.where进行排序或查询.例如,我想查询跟随者数> 500的用户,或者我想通过关注者或跟随计数来订购.
谢谢!
例:
model User
data: {
"photos"=>[
{"type"=>"facebook", "type_id"=>"facebook", "type_name"=>"Facebook", "url"=>"facebook.com"}
],
"social_profiles"=>[
{"type"=>"vimeo", "type_id"=>"vimeo", "type_name"=>"Vimeo", "url"=>"http://vimeo.com/", "username"=>"v", "id"=>"1"},
{"bio"=>"I am not a person, but a series of plants", "followers"=>1500, "following"=>240, "type"=>"twitter", "type_id"=>"twitter", "type_name"=>"Twitter", "url"=>"http://www.twitter.com/", "username"=>"123", "id"=>"123"}
]
}
Run Code Online (Sandbox Code Playgroud) 离子很棒,但如果你想留在React原生世界,我还没有找到可比的东西.有什么建议?
试图在带有rails的模式上做区别.
2.1.1 :450 > u.profiles.select("profiles.*").distinct
Profile Load (0.9ms) SELECT DISTINCT profiles.* FROM "profiles" INNER JOIN "integration_profiles" ON "profiles"."id" = "integration_profiles"."profile_id" INNER JOIN "integrations" ON "integration_profiles"."integration_id" = "integrations"."id" WHERE "integrations"."user_id" = $1 [["user_id", 2]]
PG::UndefinedFunction: ERROR: could not identify an equality operator for type json
LINE 1: SELECT DISTINCT profiles.* FROM "profiles" INNER JOIN "integ...
^
: SELECT DISTINCT profiles.* FROM "profiles" INNER JOIN "integration_profiles" ON "profiles"."id" = "integration_profiles"."profile_id" INNER JOIN "integrations" ON "integration_profiles"."integration_id" = "integrations"."id" WHERE "integrations"."user_id" = $1
ActiveRecord::StatementInvalid: …Run Code Online (Sandbox Code Playgroud) 我如何仅从Test 3以下测试中运行?
module.exports = {
'Test 1':function(){},
'Test 2':function(){}
'Test 3':function(){}
}
Run Code Online (Sandbox Code Playgroud) 得到错误:
undefined method `environment' for nil:NilClass
Extracted source (around line #5):
<head>
<title>Dossiyadata</title>
<%= stylesheet_link_tag "application", media: "all", "data-turbolinks-track" => true %>
<%= javascript_include_tag "application", "data-turbolinks-track" => true %>
<%= csrf_meta_tags %>
</head>
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导入bootstrap时.不知道为什么?使用ruby 2.1.1
宝石文件:
source 'https://rubygems.org'
# Bundle edge Rails instead: gem 'rails', github: 'rails/rails'
gem 'rails', '4.0.4'
# Use SCSS for stylesheets
gem 'sass-rails'
gem 'bootstrap-sass'
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跟踪:
sass-rails (4.0.1) lib/sass/rails/importer.rb:84:in `evaluate'
sass-rails (4.0.1) lib/sass/rails/importer.rb:70:in `engine_from_path'
sass-rails (4.0.1) lib/sass/rails/importer.rb:35:in `find'
sass (3.3.3) lib/sass/tree/import_node.rb:54:in `block in import'
sass (3.3.3) …Run Code Online (Sandbox Code Playgroud) 先前:
var debug = require('debug')('http')
, http = require('http')
, name = 'My App';
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使用es6,如何像第一行一样立即导入和调用?
import debug from 'debug'();
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是不是不?
我让我的webpack生成一个大的main.js文件(1.7mb),其中包含一个小于20-30个文件的项目,每个文件少于100行.所需的依赖项数量很少(React,Fluxible),我正在使用我能理解的每个优化插件:
module.exports = {
output: {
path: './build',
publicPath: '/public/',
filename: '[name].js'
},
debug: false,
devtool: 'eval',
target: 'web',
entry: [
'bootstrap-sass!./bootstrap-sass.config.js',
'./client.js',
],
stats: {
colors: true,
reasons: false
},
resolve: {
extensions: ['', '.js'],
alias: {
'styles': __dirname + '/src/styles',
'components': __dirname + '/src/scripts/components',
'actions': __dirname + '/src/scripts/actions',
'stores': __dirname + '/src/scripts/stores',
'constants': __dirname + '/src/scripts/constants',
'mixins': __dirname + '/src/scripts/mixins',
'configs': __dirname + '/src/scripts/configs',
'utils': __dirname + '/src/scripts/utils'
}
},
module: {
loaders: [
{ test: /\.css$/, loader: …Run Code Online (Sandbox Code Playgroud) 我试图让react-router与webpack-dev-server一起工作,但继续得不到Get/SOMEURL.这是因为webpack-dev-server正在查找该特定文件但无法找到它.我希望webpack使用react-router vs搜索文件本身.
我怎么设置它?
我的咕噜声:
'webpack-dev-server': {
options: {
hot: true,
port: 8000,
webpack: webpackDevConfig,
publicPath: '/assets/',
contentBase: './<%= pkg.src %>/'
},
start: {
keepAlive: true,
}
},
Run Code Online (Sandbox Code Playgroud) 我目前有一个用于运行linter的npm脚本.显然会输出一些错误,但是npm脚本失败而不是只显示错误并继续前进.
这是非常糟糕的,特别是当我有其他东西调用脚本,因为它奇迹般地打破了一切.我总是可以跑来npm run lint --force避免错误,但我并不总是那么--force奢侈(例如,使用git-hook).
如何设置我的脚本输出错误而不会造成混乱?
postgresql ×2
reactjs ×2
webpack ×2
babeljs ×1
ecmascript-6 ×1
git ×1
iterm ×1
iterm2 ×1
javascript ×1
json ×1
node.js ×1
npm ×1
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