在下面的代码我得到一个错误 mailServer.sendmail(gmailUser, m.to_addr, msg.as_string())
2011-08-12 17:33:02,542 ERROR send exception
Traceback (most recent call last):
File "sendmail.py", line 33, in bulksend
mailServer.sendmail(gmailUser, m.to_addr, msg.as_string()).replace(u'\xa0', '')
File "/usr/lib/python2.4/email/Message.py", line 129, in as_string
g.flatten(self, unixfrom=unixfrom)
File "/usr/lib/python2.4/email/Generator.py", line 82, in flatten
self._write(msg)
File "/usr/lib/python2.4/email/Generator.py", line 113, in _write
self._dispatch(msg)
File "/usr/lib/python2.4/email/Generator.py", line 139, in _dispatch
meth(msg)
File "/usr/lib/python2.4/email/Generator.py", line 205, in _handle_multipart
g.flatten(part, unixfrom=False)
File "/usr/lib/python2.4/email/Generator.py", line 82, in flatten
self._write(msg)
File "/usr/lib/python2.4/email/Generator.py", line 113, in _write
self._dispatch(msg)
File "/usr/lib/python2.4/email/Generator.py", line 139, in …在下面的perl代码中如何将pwd与字符串连接起来.在下文中,输出分为两个不同的行
$pwd=`pwd`;
my $string = $pwd . "/.somename";
print "$string";
我是如何使用以下代码进行反向迭代的.我应该使用reduce功能吗？
例:
for i in range(4):
print i ////0 1 2 3
我该如何以相反的顺序打印相同的内容
3 2 1 0
a=[5,2,1,4,3]
我也想使用索引反向打印上面的数组,而不是a[::-1]
,我想先打印
a[4] //get index starting from last how to achieve this
a[3]
a[2]
a[1]
a[0]
在下面的代码,我需要打印从变量输出$stout,$stderr.我怎么能这样做,而不是没有使用$ssh = Net::SSH::Perl->new？
#!/usr/bin/perl
use strict;
use warnings;
use Net::SSH::Perl;
use FindBin qw($RealBin);
use File::Basename;
use lib "/nfs/site/proj/dpg/tools/lib/perl";
use Util;
use Getopt::Std;
use Net::SSH::Perl;
use Cwd;
use File::Copy;
my $host = 'someip.com.com';
my $pass = '';
my $user = '';
my $cmd = 'pwd';
my($stdout,$stderr,$exit) = system('ssh someip.com cat /nfs/site/home/aa/test11.txt') ;
if ($stdout) {
print "Standard output is \n$stdout";
} elsif($stderr) {
print "Standard error is \n$stderr";
}
我试图从命令行获取参数并解析它,如果参数正确,则根据它调用某些函数.我是perl的新手,有人可以知道如何实现这一点
script.pl aviator #switch is valid and should call subroutine aviator()
script.pl aviator debug #valid switch and should call subroutine aviator_debug
script.pl admin debug or script.pl debug admin #valid switch and should call subroutine admin_debug()
script.pl admin #valid switch and should call subroutine admin()
script.pl dfsdsd ##invalid switch ,wrong option
我如何形成一个由b元素组成的数组(c)？
a=[1,2,"ID123","ID126","ID124","ID125"]
b=[1,"ID123","ID124","ID125","343434","fffgfgf"]
c= []
这可以在不使用列表理解的情况下完成吗？
在下面的代码点击按钮我想隐藏相对布局rl1和显示rl2但我的应用程序在按钮点击后崩溃.我做错了什么
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="wrap_content"
>
<RelativeLayout
android:id="@+id/rl1"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:background="@drawable/welcome_1">
<ImageView
android:id="@+id/button1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignParentRight="true"
android:paddingTop="360dp"
android:layout_marginRight="4dp"
android:src="@drawable/button1" />
</RelativeLayout>
<RelativeLayout
android:id="@+id/rl2"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:visibility="invisible"
android:background="@drawable/menu_2"
></RelativeLayout>
</RelativeLayout>
Java代码
public class mockupsActivity extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
// ImageButton img1 = (ImageButton)findViewById(R.id.button1);
ImageView img1 =(ImageView)findViewById(R.id.button1);
img1.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
// your code here …在下面的代码中,我试图匹配数字,可以是16位或15位数字,可以有空格或-每4位数之间.
我得到一个错误
ValueError: Cannot process flags argument with a compiled pattern
我究竟做错了什么？
import re
p_number = re.compile(r'(\d{15}|\d{16}|\d{4}[\s-]\d{4}[\s-]\d{4}[\s-]\d{4})')
c=["1234567891234567","123456789123456","1234 5678 9123 4567","1234-5678-9123-4567","1234567891111111tytyyyy"]
for a in c:
#re.search(c,p_number,flag=0)
matchObj = re.search( p_number , a, re.M|re.I)
if matchObj:
print "match found"
else:
print "No match!!"
在python中如何找到包含在单引号内的字符串
arr=["string","string'1" ,"'string2'"]
for i in arr:
if i //string enclosed in single quotes condition
print "found"
print i //which sould print only string2 in this case
是否有任何python爬虫可以从网页中提取所有数据:http://www.bestbuy.com/site/HTC+-+One+S+4G+Mobile+Phone+-+Gradient+Blue+%28T-Mobile %29/4980512.p？id = 1218587135819&skuId = 4980512&contract_desc = 在此页面中,客户评论有两个页面1和2.我想抓取他的网址并获取两个网页的内容.这是否可以使用python爬虫.
python crawler也支持所有现代GET/POST技术
在下面的字符串中,我想计算在第一个\ tCart之前出现的单词数,并忽略字符串的其余部分,我们怎么能这样做
str1="hi\thello\thow\tare\tyou\tCart\tagain\tCart"
output expected:5
str1.count() ?????