小编Tap*_*pha的帖子

如何创建一个jquery计时器,当链接被"鼠标悬停"时启动,显示1,2,3,4和5,一个接一个.然后在5上弹出一个登录框？

干杯.

这是循环.

foreach($results->results as $result){
    echo '<div id="twitter_status">';
    echo '<img src="'.$result->profile_image_url.'" class="twitter_image">';
    $text_n = $result->text; 
    echo "<div id='text_twit'>".$text_n."</div>";
    echo '<div id="twitter_small">';
    echo "<span id='link_user'".'<a href="http://www.twitter.com/'.$result->from_user.'">'.$result->from_user.'</a></span>';
    $date = $result->created_at;

    $dateFormat = new DateIntervalFormat();

    $time = strtotime($result->created_at);

    echo "<div class='time'>";

    print sprintf('Submitted %s ago',  $dateFormat->getInterval($time));

    echo '</div>';

    echo "</div>";
    echo "</div>";

有没有一种简单的方法可以在apign.site.com等codeigniter上创建子域名？

该函数应该更新数据库中的值.

这是代码:

//Functions
//Function to Update users networth
function update_net($name)
    {
    //Get worth & balance at the time
    $sql_to_get_worth_balance = "SELECT * FROM user WHERE username = '$name'";
    $sql_query = mysql_query($sql_to_get_worth_balance);
    while ($rows = mysql_fetch_assoc($sql_query))
    {
     $worth = $rows['worth'];
     $balance_ = $rows['cash_balance'];
    }
    //Get net_worth  now
    $new_net_worth = $worth + $balance;
    //Update net_worth
    $sql_for_new_worth = "UPDATE user SET net_worth = '$new_net_worth'";
    $sql_worth_query = mysql_query($sql_worth);
    }

它在这里使用:

//Get username
$username = $_SESSION['username'];

if (isset($username))
{
  //Update networth
  $update_worth = update_net($username);

不是真实的信息:

$ ssh-keygen -t rsa -C"tekkub@gmail.com"生成公共/私有rsa密钥对.输入要保存密钥的文件(/c/Users/Tekkub/.ssh/id_rsa):

ssh.txt

我在这里输入了一个文件名.不确定我是否应该

输入密码(无密码短语为空):

我被困在这里.我打字,它不起作用

我仍然是在我的db_design中实现连接的新手,我不确定这个SQL是否有效.

"SELECT * FROM notes JOIN small_note ON notes_id = '$id' AND authname = '$author' AND bookname = '$book' AND user = '$username'"

这样更容易阅读:

"SELECT * FROM notes
    JOIN small_note ON notes_id = '$id'
    AND authname = '$author'
    AND bookname = '$book'
    AND user = '$username'";

如何在PHP中将所有数组值一起添加？这有功能吗？

这是te代码:

<?php

//Starting session

session_start();

//Includes mass includes containing all the files needed to execute the full script
//Also shows homepage elements without customs

require_once ('includes/mass.php');

$username = $_SESSION['username'];

if (isset($username))

{   

//Query database for the users networths

$sq_l = "SELECT * FROM user";

$sql_query_worth = mysql_query($sq_l);

while ($row = mysql_fetch_assoc($sql_query_worth))

      {

         $dbusername = $row['username'];


      } 

      echo $dbusername;

}
?>

这是代码:

<?php

//Starting session

session_start();

//Includes mass includes containing all the files needed to execute the full script
//Also shows homepage elements without customs

require_once ('includes/mass.php');

$username = $_SESSION['username'];

if (isset($username))

{   

//Query database for the users networths

$sq_l = "SELECT * FROM user ORDER BY worth";

$sql_query_worth = mysql_query($sq_l);

while ($row = mysql_fetch_assoc($sql_query_worth))

      {

         $dbusername = $row['username'];

         $dbworth    = $row['worth'];

            foreach ($dbusername as $dbuser)

                {
                    echo ". USER: ".$dbuser." Has a networth of:  ".$dbworth;

                }
      }               
}

?>

有三个结果.这是错误. …