小编Ami*_*iri的帖子

我正在使用java7,jboss7,ojdbc7,hibernate 4.表有一个CLOB列,在域类中代码是这样的:

@Lob private String MyClob;

我在查询时遇到这个奇怪的错误,这是不一致的.

Caused by: javax.persistence.PersistenceException: org.hibernate.HibernateException: IOException occurred reading text
        at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1387)
        at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1310)
        at org.hibernate.ejb.QueryImpl.getResultList(QueryImpl.java:273)
        at org.hibernate.ejb.criteria.CriteriaQueryCompiler$3.getResultList(CriteriaQueryCompiler.java:254)
        ...
        ... 102 more
Caused by: org.hibernate.HibernateException: IOException occurred reading text
        at org.hibernate.type.descriptor.java.DataHelper.extractString(DataHelper.java:94)
        at org.hibernate.type.descriptor.java.DataHelper.extractString(DataHelper.java:280)
        at org.hibernate.type.descriptor.java.StringTypeDescriptor.wrap(StringTypeDescriptor.java:89)
        at org.hibernate.type.descriptor.java.StringTypeDescriptor.wrap(StringTypeDescriptor.java:39)
        at org.hibernate.type.descriptor.sql.ClobTypeDescriptor$1.doExtract(ClobTypeDescriptor.java:60)
        at org.hibernate.type.descriptor.sql.BasicExtractor.extract(BasicExtractor.java:64)
        at org.hibernate.type.AbstractStandardBasicType.nullSafeGet(AbstractStandardBasicType.java:261)
        at org.hibernate.type.AbstractStandardBasicType.nullSafeGet(AbstractStandardBasicType.java:257)
        at org.hibernate.type.AbstractStandardBasicType.nullSafeGet(AbstractStandardBasicType.java:247)
        at org.hibernate.type.AbstractStandardBasicType.hydrate(AbstractStandardBasicType.java:332)
        at org.hibernate.persister.entity.AbstractEntityPersister.hydrate(AbstractEntityPersister.java:2912)
        at org.hibernate.loader.Loader.loadFromResultSet(Loader.java:1672)
        at org.hibernate.loader.Loader.instanceNotYetLoaded(Loader.java:1604)
        at org.hibernate.loader.Loader.getRow(Loader.java:1504)
        at org.hibernate.loader.Loader.getRowFromResultSet(Loader.java:712)
        at org.hibernate.loader.Loader.processResultSet(Loader.java:942)
        at org.hibernate.loader.Loader.doQuery(Loader.java:910)
        at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:341)
        at org.hibernate.loader.Loader.doList(Loader.java:2522)
        at org.hibernate.loader.Loader.doList(Loader.java:2508)
        at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2338)
        at org.hibernate.loader.Loader.list(Loader.java:2333)
        at org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:490) …

我有一个以下格式的JavaScript对象

{
"Node1": [
    {
    "Node2": "node2detail1",
    "Node3": "node3detail1",
    "Node4": [
        "node4detail1",
        ]
    },
    {
    "Node2": "node2detail2",
    "Node3": "node3detail2",
    "Node4": [
        "node4detail2",
        ]
    },
    {
    "Node2": "node2detail3",
    "Node3": "node3detail3",
    "Node4": [
        "node4detail3",
        ]
    }
]}

是否可以编写一个jsonpath表达式,该表达式将导致以下格式的JavaScript对象？目的是按键过滤.

{
"Node1": [
    {
    "Node2": "node2detail1",
    "Node3": "node3detail1",
    },
    {
    "Node2": "node2detail2",
    "Node3": "node3detail2",
    },
    {
    "Node2": "node2detail3",
    "Node3": "node3detail3",
    }
]}