小编Sam*_*vis的帖子

假设我在C#中有一个对象:

public class Person
{
    public string Name{get;set;}
    public int Age{get;set;}
}

要在C#中从此列表中选择名称,我将执行以下操作:

List<string> names = person.Select(x=>x.Name).ToList();

我如何在Java 8中做同样的事情？

此处的 AWS 文档表明支持 SQL 查询：https://aws.amazon.com/about-aws/whats-new/2019/05/amazon-elasticsearch-service-sql-support/

此页面显示语法： https://docs.aws.amazon.com/elasticsearch-service/latest/developerguide/sql-support.html

POST elasticsearch_domain/_opendistro/_sql
{
  "query": "SELECT * FROM my-index LIMIT 50"
}

在 Kibana 开发工具中运行以下命令

POST my_domain/_opendistro/_sql
{
  "query": "SELECT * FROM my-index LIMIT 50"
}

给出错误

{
  "error": {
    "root_cause": [
      {
        "type": "invalid_type_name_exception",
        "reason": "Document mapping type name can't start with '_', found: [_opendistro]"
      }
    ],
    "type": "invalid_type_name_exception",
    "reason": "Document mapping type name can't start with '_', found: [_opendistro]"
  },
  "status": 400
}

我的ElasticSearch版本是6.7。