我已经尝试了一段时间但是无法让它发挥作用.我试图有一个方法来反转整数而不使用字符串或数组.例如,123应以整数形式反转为321.
我的第一次尝试:
/** reverses digits of integer using recursion */
public int RevDigs(int input)
{
int reverse = 0;
if(input == 0)
{
return reverse;
}
int tempRev = RevDigs(input/10);
if(tempRev >= 10)
reverse = input%10 * (int)Math.pow(tempRev/10, 2) + tempRev;
if(tempRev <10 && tempRev >0)
reverse = input%10*10 + tempRev;
if(tempRev == 0)
reverse = input%10;
return reverse;
}//======================
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我也尝试过使用它,但似乎搞乱了中间数字:
/** reverses digits of integer using recursion */
public int RevDigs(int input)
{
int reverse = 0;
if(input == …Run Code Online (Sandbox Code Playgroud) 我正在学习C++,并且我被要求使用while函数编写代码.代码运行,但它给出不打印行Dear ....我在这做错了什么?
cout << "Hello! Please write your recipient and the letter, then press enter:\n";
string name{ "" };
string current{ "" };
string letter{ "" };
cin >> name;
while (cin >> current){
if (current != name){
letter += " " + current;
}
}
cout << "Dear " << name << "," << letter;
keep_window_open();
return 0;
Run Code Online (Sandbox Code Playgroud) 我有这个代码序列:
printf("%p\n", gameGUI);
printf("label %p\n", gameGUI->labelRoundType);
gui_setRoundType(gameGUI->labelRoundType,
gameGUI->game->rounds[roundId]);
printf("label %p\n", gameGUI->labelRoundType);
printf("%p\n", gameGUI);
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函数gui_setRoundType的代码.
int gui_setRoundType(GtkWidget *roundTypeLabel, struct Round *round)
{
if (round == NULL)
return ROUND_NULL;
if (roundTypeLabel == NULL)
return POINTER_NULL;
char type[1] = { '\0' };
intToChar(round->roundType, type);
gtk_label_set_text(GTK_LABEL(roundTypeLabel), type);
return NO_ERROR;
}
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GameGUI结构的代码:
struct GameGUI {
struct Game *game;
struct Select *select;
struct PlayerCards *playerCards;
struct PlayersGUI *playersGUI;
struct CardsFromTable *cardsFromTable;
struct BidGUI *bidGUI;
GtkWidget *windowTable;
GtkWidget *fixedTable;
GtkWidget *buttonShowScore;
GtkWidget *imageTrump;
GtkWidget *labelRoundType;
GtkWidget *labelNoOfBids; …Run Code Online (Sandbox Code Playgroud) 我已经看到以这种方式声明的某些函数:
char* encipher(const char *src, char *key, int is_encode);
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我不明白这一部分:
char* encipher
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数据类型后的星号是什么意思?
嗨,我已经创建了使用HashSet数组的代码.我是Java编程的新手,我想知道如何完成这两项任务:
*从HashSet数组中按索引获取项目*显示列表中每个项目的平均长度
我的代码不长,所以我在这里粘贴整个代码.感谢你的帮助.
public class MainActivity extends Activity {
Button aButton; // Global Scope
Button sButton;
TextView text2;
EditText eText;
HashSet<String> list = new HashSet<String>();
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.new_layout);
aButton = (Button) this.findViewById(R.id.button1);
text2 = (TextView) this.findViewById(R.id.textView1);
//Clickable Saved Input will display alert
text2.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Toast.makeText(getApplicationContext(), "Complete!", Toast.LENGTH_LONG).show();
}
});
aButton.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
list.add("Books");
list.add("Newspapers");
list.add("Magazines");
String listString = "";
for (String s …Run Code Online (Sandbox Code Playgroud) 我有作业来检查数字是一个两位数还是一位数而不使用if语句.谢谢你的帮助!
public class SchoolTest {
public static void main(String[] args) {
Scanner reader = new Scanner(System.in);
int x;
System.out.println("Please enter a number");
x = reader.nextInt();
if ((x > 9 && x < 100) || (x < -9 && x > -100)) {
System.out.println(true);
main(args);
} else {
System.out.println(false);
main(args);
}
}
}
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