小编use*_*937的帖子

Javascript对象Big-O

来自Java,Javascript对象让我想起了Java中的HashMap.

使用Javascript:

var myObject = {
    firstName: "Foo",
    lastName: "Bar",
    email: "foo@bar.com"
};
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Java的:

HashMap<String, String> myHashMap = new HashMap<String, String>();
myHashMap.put("firstName", "Foo");
myHashMap.put("lastName", "Bar");
myHashMap.put("email", "foo@bar.com");
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在Java HashMap中,它使用密钥的hashcode()函数来确定存储和检索的存储区位置(条目).大多数时候,对于诸如put()和get()之类的基本操作,性能是恒定时间,直到发生哈希冲突,这对于这些基本操作变为O(n),因为它形成链表以便存储相互冲突的条目.

我的问题是:

  1. Javascript如何存储对象?
  2. 运营的表现如何?
  3. 是否会出现任何会像Java中那样降低性能的碰撞或其他情况

谢谢!

javascript performance big-o

16
推荐指数
1
解决办法
2000
查看次数

Spring Batch Admin,无法替换占位符'batch.business.schema.script'

尝试将Spring Batch Admin添加到现有的Spring Batch项目中.

我已经使用spring-batch-admin-resources和spring-batch-admin-manager更新了web.xml

我的设置:

src/main/resources /下

我添加了2个属性文件.1是batch-default-properties,它是一个空文件,另一个是batch-sqlserver.properties,其中包含以下内容:

batch.jdbc.driver=com.microsoft.sqlserver.jdbc.SQLServerDriver    batch.jdbc.url=jdbc:sqlserver://xxx.xxx.xxx:1433;DatabaseName=SpringBatch
batch.jdbc.user=user
batch.jdbc.password=password
batch.jdbc.testWhileIdle=false
batch.jdbc.validationQuery=
batch.drop.script=/org/springframework/batch/core/schema-drop-sqlserver.sql
batch.schema.script=/org/springframework/batch/core/schema-sqlserver.sql
batch.database.incrementer.class=org.springframework.jdbc.support.incrementer.SqlServerMaxValueIncrementer
batch.lob.handler.class=org.springframework.jdbc.support.lob.DefaultLobHandler
batch.business.schema.script=business-schema-sqlserver.sql
batch.database.incrementer.parent=columnIncrementerParent
batch.grid.size=2
batch.jdbc.pool.size=6
batch.verify.cursor.position=true
batch.isolationlevel=ISOLATION_SERIALIZABLE
batch.table.prefix=BATCH_
batch.data.source.init=false
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webapp/META-INF/spring/batch/override /下,我添加了带内容的data-source-context.xml:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">

       <bean id="dataSource" class="org.springframework.jndi.JndiObjectFactoryBean">
              <property name="jndiName">
                     <value>java:jboss/datasources/springBatchDB</value>
              </property>
       </bean>
</beans>
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这是在JBoss EAP 6.3中运行的.每次我启动服务器时,都会出现以下异常:

11:58:36,116 WARN  [org.springframework.web.context.support.XmlWebApplicationContext] (ServerService Thread Pool -- 112) Exception encountered during context initialization - cancelling refresh attempt: org.springframework.beans.factory.BeanDefinitionStoreException: Invalid bean definition with name 'org.springframework.jdbc.datasource.init.DataSourceInitializer#0' defined in null: Could …
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java spring spring-batch spring-batch-admin

5
推荐指数
1
解决办法
4519
查看次数

无法使用JSON实体测试Jax-rs

我正在尝试通过遵循此https://jersey.java.net/documentation/latest/test-framework.html来测试Jax-rs资源,
并且我正在使用容器jersey-test-framework-provider-jdk-http

我可以声明状态码。但是,当我尝试读取实体时,出现异常:

javax.ws.rs.ProcessingException: Unable to find a MessageBodyReader of content-type application/json and type class java.lang.String
    at org.jboss.resteasy.core.interception.ClientReaderInterceptorContext.throwReaderNotFound(ClientReaderInterceptorContext.java:39)
    at org.jboss.resteasy.core.interception.AbstractReaderInterceptorContext.getReader(AbstractReaderInterceptorContext.java:73)
    at org.jboss.resteasy.core.interception.AbstractReaderInterceptorContext.proceed(AbstractReaderInterceptorContext.java:50)
    at org.jboss.resteasy.client.jaxrs.internal.ClientResponse.readFrom(ClientResponse.java:248)
    at org.jboss.resteasy.client.jaxrs.internal.ClientResponse.readEntity(ClientResponse.java:181)
    at org.jboss.resteasy.specimpl.BuiltResponse.readEntity(BuiltResponse.java:217)
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我的资源分类:

@Path("/")
public class SampleResource {
    @GET
    @Path("/health")
    @Produces(MediaType.APPLICATION_JSON)
    public String getServiceStatus() {
        return "{\"Status\": \"OK\"}";
    }    
}
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我的测试班:

public class TestSampleResource extends JerseyTest {
    @Override
    protected Application configure() {
        return new ResourceConfig(SampleResource.class);
    }

    @Test
    public void testHealthEndpoint() {            
        Response healthResponse = target("health").request(MediaType.APPLICATION_JSON).get();

        Assert.assertEquals(200, healthResponse.getstatus());  // works

        String body …
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java junit jax-rs jersey resteasy

1
推荐指数
1
解决办法
914
查看次数