小编She*_*mes的帖子

SELECT Batch.NumStud 
FROM Batch 
WHERE CourseID='$courseid'
INNER JOIN Course 
ON Batch.CourseID=Course.CourseID"

一个错误,说 mysql_fetch_array(): supplied argument is not a valid MySQL result resource in <b>F:\AppServ\www\anNoECourse.php

显示.编写此代码是为了将数据输入谷歌图表.