对我来说,做以下事情似乎是合乎逻辑的:
var AvatarSchema = new Mongoose.Schema({
type: String,
url: String
});
var UserSchema = new Mongoose.Schema({
avatars: [AvatarSchema],
email: String,
name: String,
salt: String,
token: String
});
var ThinUserSchema = new Mongoose.Schema({
avatars: [AvatarSchema],
email: String,
firstname: String,
lastname: String,
});
var QuestionSchema = new Mongoose.Schema({
question: String,
users: [ThinUserSchema]
});
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然后是...do如下:
var question = new Question({
question: 'Wut?',
users: users //where users is an array of instances of a user model of the UserSchema
});
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在这里,我希望问题的用户部分可以填充头像,电子邮件,名字和姓氏...但是,由于用户/头像已经有_id,因此这些不会持续存在.
希望在ES中进行经典的OpenGL鼠标选择.我不想使用第三方库,GLU端口和OpenGL名称堆栈等.这几乎留下了逆视图变换和光线交叉,对吗?
在以下的帮助下,我已经走得很远:http : //trac.bookofhook.com/bookofhook/trac.cgi/wiki/MousePicking http://eigenclass.blogspot.com/2008/10/opengl-es-picking-使用射线boundingbox.html
..但我还没有.这也是一个更容易的方式!
这是一些代码:
-(void)handleTouch:(CGPoint)point {
GLfloat width = backingWidth;
GLfloat height = backingHeight;
GLfloat x = point.x;
GLfloat y = point.y;
GLfloat z = 0.0f;
//viewport -> normalized dev coord -> clip
GLfloat n[] = {
2 * x / width - 1,
2 * y / height,
2 * z - 1,
1
};
float fov = 45.0f * (M_PI / 180.0f);
float near = 0.01, far = 10.0f;
float aspect = (float)backingWidth / …Run Code Online (Sandbox Code Playgroud) 我正在尝试使用以下方法从节点中的s3检索图像:
app.get('/photos', function(req, res, next) {
var data = '';
s3.get('/tmp/DSC_0904.jpg').on('response', function(s3res){
console.log(s3res.statusCode);
console.log(s3res.headers);
s3res.setEncoding('binary');
s3res.on('data', function(chunk){
data += chunk;
});
s3res.on('end', function() {
res.contentType('image/jpeg');
res.send(data);
});
}).end();
});
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我愿意接受为什么这不起作用的建议.
RabbitMQ + Web Stomp非常棒.但是,我有一些主题我想要以只读或只写方式保密.
看来保护这些的唯一机制是使用rabbitmqctl.我可以创建一个vhost,一个用户,然后应用一些权限.然而,这就是Stomp和Rabbit实现开始崩溃的地方.
主题采取形式:/ topic/blah in stomp,它使用路由键"blah"路由到Rabbit中的"amq.topic".似乎没有办法为路由键设置权限.似乎:
rabbitmqctl set_permissions -p vhost user ".*" ".*" "^amq\.topic"
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是我能做的最好的,这仍然是"所有"主题.我也研究过交流,但是在javascript中无法动态定义这些交换.
我在这里错过了什么吗?
参考:http://www.rabbitmq.com/blog/2012/05/14/introducing-rabbitmq-web-stomp/
UIVideoEditorController尽管videoQuality在iOS 8.2和iOS 8.3中设置了属性,但修剪过的视频仍会被压缩并失去质量.
let controller = segue.destinationViewController as! UIVideoEditorController
if let pathStr = mediaFile.pathStr {
if UIVideoEditorController.canEditVideoAtPath(pathStr as String) {
controller.delegate = self
controller.videoMaximumDuration = 30
controller.videoPath = pathStr as String
controller.videoQuality = .TypeHigh
} else {
showAlert("Can not edit video")
}
}
}
Run Code Online (Sandbox Code Playgroud) 我希望我的纹理完全消失,使用以下片段着色器:
varying mediump vec2 text_coord_out;
uniform sampler2D sampler;
void main()
{
gl_FragColor = texture2D(sampler, text_coord_out);
gl_FragColor.w *= 0.0;
}
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...it没有.我也试过gl_FragColor.a.思考?
我尝试将Heroku与Mongo一起用于Express.js项目.挣扎着连接到mongohq.日志输出:
connstring是:mongodb:// heroku:XXXXXXXXXXXXXXXXXXXXXXXX@staff.mongohq.com:10073/app676842主持人是:staff.mongohq.com
app.configure(function() {
app.set('connstring', process.env.MONGOHQ_URL
|| ('mongodb://' + app.set('m_host') + '/' + app.set('m_database')));
console.log('connstring is: ' + app.set('connstring'));
var uri = parseUri(app.set('connstring'));
console.log('host is: ' + uri.host);
app.use(express.bodyParser());
app.use(express.cookieParser());
// use connect-mongo as session middleware
app.use(express.session({
secret: 'topsecret',
store: new store({ db: app.set('m_database'), host: uri.host })
}));
app.use(express.methodOverride());
app.use(app.router);
// use express logger
app.use(express.logger({ format: '\x1b[1m:method\x1b[0m \x1b[33m:url\x1b[0m :response-time ms' }));
app.use(express.static(__dirname + '/public'));
});
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