正如您在下面的JS Fiddle中看到的那样,我只能在其中一个输入框旁边显示小的Datepicker图标.我需要它出现在两者旁边.
但是,将"id"更改为"class"不起作用,导致两个图标都消失.
HTML:
<title>jQuery UI Datepicker - Icon trigger</title>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script src="//ajax.googleapis.com/ajax/libs/jqueryui/1.10.3/jquery-ui.min.js"></script>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script src="http://code.jquery.com/ui/1.10.3/jquery-ui.js"></script>
<script>
$(function() {
$( "#datepicker" ).datepicker({
showOn: "button",
buttonImage: "calendar.gif",
buttonImageOnly: true
});
});
</script>
<p>Date: <input type="text" id="datepicker" /></p>
<p>Date: <input type="text" id="datepicker" /></p>
CSS:
<link rel="stylesheet" href="http://code.jquery.com/ui/1.10.3/themes/smoothness/jquery-ui.css" />
<link rel="stylesheet" href="/resources/demos/style.css" />
Run Code Online (Sandbox Code Playgroud) 我最近改变了我的标题以保持固定.标题是完美的,但它隐藏了一半的内容.我尝试更改内容的"顶部"设置,但不会改变结果.
HTML:
<div class="gridContainer clearfix">
<div id="LayoutDiv1">We are here to help</div>
<form action="website.php" method="POST">
<div id="LayoutDiv3"> Names:
<input type="text" name="user"/>
Gender<FONT COLOR="#FF0000">*</FONT>
<select name="Gender[]" double="double">
<option value="Female">Female</option>
<option value="Male">Male</option>
</select>
</div>
<div id="Components"></div>
<div id="Food"><h1>Dietary conditions:</h1>
Gluten Free
<input type="checkbox" name="GlutenFree" value="Yes" />
<br>
Diary Free
<input type="checkbox" name="DairyFree" value="Yes" />
<br>
No Softdrink
<input type="checkbox" name="NoSoftDrink" value="Yes" />
<br>
Halal
<input type="checkbox" name="Halal" value="Yes" />
<br>
Vegetarian
<input type="checkbox" name="Vegetarian" value="Yes" />
<br>
No Nuts
<input …Run Code Online (Sandbox Code Playgroud) 我试图从数组中删除重复项.如下所示,代码中的结果列表包含两个Sugar和Coffee事件.如何有效地从列表中删除重复项?(这个代码实际上要长得多,并且包含400多个元素).
<?php
$FoodList = array();
$zb = Milk
$cd = Bread
$dc = Orange
$ce = Apple
$ec = KiwiFruit
$cg = GrapeFruit
$gc = Cucumber
$ch = Biscuit
$hc = Caramel
$dv = Juice
$ci = SoftDrink
$ic = Banana
$cj = Tea
$cl = Sugar
$jc = Coffee
$ck = Yoghurt
$kc = Pizza Base
$lc = Tuna
if ($_POST['Dairy'] == 'Yes') { //Radio check box
array_push($FoodList, $zb, $cd, $dc, $ce, $ec);
}
if ($_POST['GlutenFree'] == 'Yes') { …Run Code Online (Sandbox Code Playgroud) 我有一个完美的CSS网页,我想运行一个"datepicker"JQuery脚本.
唯一的问题是,当我添加所需的脚本时
<script src="respond.min.js"></script>
<script type="text/javascript" src="../AllSet/jquery-ui-1.10.3.custom.css"></script>
<script type="text/javascript" src="../AllSet/jquery-ui-1.10.3.custom.min.css"></script>
<script type="javascript"...
Run Code Online (Sandbox Code Playgroud)
在Dreamweaver的设计视图中无法看到网页,一切似乎都缺失了.
插入JQuery脚本时通常会发生这种情况吗?
任何建议都会非常感激,我是JQuery的新手,我似乎找不到为什么会发生这种情况的答案(而且几乎每次都会发生).
谢谢!
安德鲁
html ×3
css ×2
datepicker ×2
jquery-ui ×2
class ×1
dreamweaver ×1
duplicates ×1
header ×1
jsfiddle ×1
php ×1