我正在使用Spring3.2.0版本,所以我试图写下面的applicationContext.xml文件
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context"
xmlns:jee="http://www.springframework.org/schema/jee" xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-3.0.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd">
<!--
This will automatically locate any and all property files you have
within your classpath, provided they fall under the META-INF
directory. The located property files are parsed and their values can
then be used within application context files in the form of
${propertyKey}.
-->
<context:property-placeholder location="classpath*:*.properties" />
</beans>
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但是这个xml文件在Eclipse Editor中给出了错误
Multiple annotations found at this …Run Code Online (Sandbox Code Playgroud) 我有一个像这样的字符串
"myValue"."Folder"."FolderCentury";
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我想从点(".")拆分.我正在尝试使用以下代码:
String a = column.replace("\"", "");
String columnArray[] = a.split(".");
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但是columnArray空无一人.我在这做错了什么?
我想在这里再添加一个东西,其可能的String数组对象将包含spitted值,如下面提到的只有两个对象而不是三个.
columnArray[0]= "myValue"."Folder";
columnArray[1]= "FolderCentury";
Run Code Online (Sandbox Code Playgroud) 我试图 通过Egit 将Github 项目导入我的eclipse并使用URI,Host等,因为你可以检查屏幕截图,当我给我的github userId /密码我得到错误看到附加屏幕截图
或者这个例外.
https://github.com:22/michaelisvy/hibernate-4-spring-3.1-samples: cannot open git-upload-pack:
https://github.com:22/michaelisvy/hibernate-4-spring-3.1-samples: cannot open git-upload-pack
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我做错了吗?或者我们不能导入这样的其他项目?

我做了一个弹出窗口。
Window window = (Window)Executions.createComponents("./org.zul", null, **map**);
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./org.zul有一个EditController.java这个控制器如何获取地图?谢谢
我只是查看了一些代码,并System在很多地方看到过
System.out.println();
System.exit();
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等等
这个类的主要目的是提供系统资源吗?系统资源是否意味着Java相关资源?