小编Ste*_*n_W的帖子

我有以下(作为示例)XML文件和XSD.

<?xml version="1.0" encoding="utf-8" ?>
<foo>
  <DateVal>2010-02-18T01:02:03</DateVal>
  <TimeVal>PT10H5M3S</TimeVal>
</foo>

和

version="1.0" encoding="utf-8"?>
<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema">
  <xs:element name="foo">
    <xs:complexType>
      <xs:sequence>
        <xs:element name="DateVal" type="xs:dateTime" />
        <xs:element name="TimeVal" type="xs:duration" />
      </xs:sequence>
    </xs:complexType>
  </xs:element>
</xs:schema>

然后是以下C#代码:

  static void Main(string[] args)
  {
     XmlDocument xd = new XmlDocument();
     XmlSchema xs;
     using (var fs = File.OpenRead(FilePath + "SimpleFields.xsd"))
     {
        xs = XmlSchema.Read(fs, null);
     }

     xd.Schemas.Add(xs);
     xd.Load((FilePath + "SimpleFields.xml"));
     xd.Validate(null);

     var el_root = xd.DocumentElement;

     var el_date = (XmlElement)el_root.SelectSingleNode("./DateVal");
     //WANTED: el_date.Value = 2010-02-18 01:02:03 (as a DateTime Object) …

我是否忘记了显而易见的,或者是"手动"比较器最好的方法？

基本上,我只想比较类型(小)字节数组的内容.如果所有字节都匹配,则结果应为true,否则为false.

我期待找到那个Array.Equals或者Buffer.Equals会有所帮助.

示范代码:

  var a = new byte[]{1, 2, 3, 4, 5};
  var b = new byte[]{1, 2, 3, 4, 5};
  Console.WriteLine(string.Format("== : {0}", (a == b)));
  Console.WriteLine(string.Format("Equals : {0}", a.Equals(b)));
  Console.WriteLine(string.Format("Buffer.Equals : {0}", Buffer.Equals(a, b)));
  Console.WriteLine(string.Format("Array.Equals = {0}", Array.Equals(a, b)));
  Console.WriteLine(string.Format("Manual_ArrayComparer = {0}", ArrayContentsEquals(a, b)));

手动功能:

/// <summary>Returns true if all elements of both byte-arrays are identical</summary>
public static bool ArrayContentsEquals(byte[] a, byte[] b, int length_to_compare = int.MaxValue)
{
  if (a == null || …