我已经阅读了这个解决方案 tic(), toc() functions
tic <- function(gcFirst = TRUE, type=c("elapsed", "user.self", "sys.self"))
{
type <- match.arg(type)
assign(".type", type, envir=baseenv())
if(gcFirst) gc(FALSE)
tic <- proc.time()[type]
assign(".tic", tic, envir=baseenv())
invisible(tic)
}
toc <- function()
{
type <- get(".type", envir=baseenv())
toc <- proc.time()[type]
tic <- get(".tic", envir=baseenv())
print(toc - tic)
invisible(toc)
}
tic();
-----code----
toc();
elapsed
0.15
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但我想在几毫秒内获得很多精度?
我也在用这个
ptm <- proc.time()
---code
proc.time() - ptm
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得到这个
user system elapsed
1.55 0.25 1.84
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如何获得更多小数或更精确?
我有一栏:
0.0677
0.0584
0.0487
0.0453
0.0394
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什么指令将获得以下输出
0.0677 0 0 0 0
0 0.0584 0 0 0
0 0 0.0487 0 0
0 0 0 0.0453 0
0 0 0 0 0.0394
Run Code Online (Sandbox Code Playgroud) 如何确定MATLAB向量中值的相对频率?
vector = [ 2 2 2 2 1 1 1 2 2 1 1 1 2 2 2 2 1 2 ];
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什么函数会返回每个唯一元素的出现次数?
有这个python代码
edges = [(0, [3]), (1, [0]), (2, [1, 6]), (3, [2]), (4, [2]), (5, [4]), (6, [5, 8]), (7, [9]), (8, [7]), (9, [6])]
graph = {0: [3], 1: [0], 2: [1, 6], 3: [2], 4: [2], 5: [4], 6: [5, 8], 7: [9], 8: [7], 9: [6]}
cycles = {}
while graph:
current = graph.iteritems().next()
cycle = [current]
cycles[current] = cycle
while current in graph:
next = graph[current][0]
del graph[current][0]
if len(graph[current]) == 0:
del graph[current]
current = …Run Code Online (Sandbox Code Playgroud) 我正在VB.net中开发一个程序,并使用System.Data.SQLite预编译的二进制文件用于.NET,但它不适用于x64架构,我得到了经典的文化问题而没有加载正确的文件.
System.BadImageFormatException:
Could not load file or assembly 'System.Data.SQLite, Version=1.0.65.0, Culture=neutral,
PublicKeyToken=db937bc2d44ff139' or one of its dependencies. An attempt was made to load a program with an incorrect format.
File name: 'System.Data.SQLite,
Version=1.0.65.0,
Culture=neutral,
PublicKeyToken=db937bc2d44ff139'
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有没有办法只使用一个dll,可能:
你认为是其他更好的想法,因为我只想制作一个编译,而不是x32和x64的其他编辑.
例如(32位):
Private Shared Sub OpenConection(ByRef Conn As SQLite.SQLiteConnection)
Conn = New SQLite.SQLiteConnection("Data Source=" & System.Environment.CurrentDirectory & "\database.db")
Conn.Open()
End Sub
Private Shared Sub CloseConection(ByRef Conn As SQLite.SQLiteConnection)
Conn.Close()
Conn.Dispose()
Conn = Nothing
End Sub
Public Shared …Run Code Online (Sandbox Code Playgroud) 我在一个类中有几个数组
我想实现toString()来打印所有值.
这该怎么做?
public String var1[];
public int var2[];
public String var3[][];
public int var4[];
public int var5[][];
public String toString() {
for(String s : var1) {
System.out.println(s.toString());
}
return null;
}
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打印所有var1 []内容,但如何打印所有?我是否必须为每一个都设置一个循环?
在组合数学中,Langford配对,也称为Langford序列,是2n数字序列1, 1, 2, 2, ..., n,n 的排列,其中两个分开一个单元,两个分开两个单元,更一般地,每个数字的两个副本k是k个单位.
例如:
Langford配对n = 3由序列给出2,3,1,2,1,3.
haskell或中解决这个问题的好方法是什么?C--------------------------编辑----------------------
怎么样我们可以定义数学规则,将@ Rafe的代码放入haskell中
是否有可能以编程方式训练识别器给出.wavs而不是与麦克风交谈?
如果是这样,怎么做?,目前我有代码在0.wav文件中对音频执行识别,并将识别的文本写入控制台.
Imports System.IO
Imports System.Speech.Recognition
Imports System.Speech.AudioFormat
Namespace SampleRecognition
Class Program
Shared completed As Boolean
Public Shared Sub Main(ByVal args As String())
Using recognizer As New SpeechRecognitionEngine()
Dim dictation As Grammar = New DictationGrammar()
dictation.Name = "Dictation Grammar"
recognizer.LoadGrammar(dictation)
' Configure the input to the recognizer.
recognizer.SetInputToWaveFile("C:\Users\ME\v02\0.wav")
' Attach event handlers for the results of recognition.
AddHandler recognizer.SpeechRecognized, AddressOf recognizer_SpeechRecognized
AddHandler recognizer.RecognizeCompleted, AddressOf recognizer_RecognizeCompleted
' Perform recognition on the entire file.
Console.WriteLine("Starting asynchronous recognition...")
completed = False …Run Code Online (Sandbox Code Playgroud) 你能举一个在matlab中使用支持向量机(SVM)对4个类进行分类的例子:
atribute_1 atribute_2 atribute_3 atribute_4 class
1 2 3 4 0
1 2 3 5 0
0 2 6 4 1
0 3 3 8 1
7 2 6 4 2
9 1 7 10 3
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