小编Toà*_*oàn的帖子

我有两个字符串:

a = 'ha? nô?i'
b = 'hà n?i'

当我与它们进行比较时a == b,它会返回false.

我检查了字节码:

a.bytes = [104, 97, 204, 128, 32, 110, 195, 180, 204, 163, 105]
b.bytes = [104, 195, 160, 32, 110, 225, 187, 153, 105]

原因是什么？我怎样才能修复它以便a == b返回true？

这是我的代码,HTML:

<div id="myApp">
   <div class="items">
      <div class="item" v-for="quiz in quizzes" :key="quiz.id"}
         <span>{{ quiz.question }}</span>
         <span v-if="selected[quiz.key]">{{ quiz.answer }}</span>
         <a href: "#" v-on:click="quizSelect(quiz.key, $event)">Select</a>
      </div>
   </div>
</div>

JS代码:

new Vue({
   el: '#myApp'
   data: {
      selected: {},
      quizzes: [
         {
            key: 'k1',
            question: 'This is question 1',
            answer: 'This is answer 1'
         },
         {
            key: 'k2',
            question: 'This is question 2',
            answer: 'This is answer 2'
         }
      ]
   },
   methods: {
      quizSelect: function(key, e) {
         e.preventDefault();
         this.selected[key] = 'selected';
      }
   }
}) …

我有两个看起来像这样的数组:

数组1:

    Array
    (
        [0] => name
        [1] => age
        [2] => job
    )

数组2:

    Array
    (
        [0] => name
        [1] => toan
        [2] => age
        [3] => 21
        [4] => job
        [5] => coder
    )

现在,我想从键中获取值0, 2, 4,并使这些值成为自己的键,指向1, 3, 5数组中键的值,如下所示:

Array
(
    [name] => toan
    [age] => 21
    [job] => coder
)

什么是简单快捷的方法呢？

基本上，这是正常的代码：

class Foo
   def hi
      # your code here....
   rescue => e
      # Raise error here
   end

   def hello
      # your code here...
   rescue => e
      # Raise error here
   end
end

但在 PHP 中，我可以使用__call魔术方法创建抽象类，如下所示：

class FooAbstract {
    public function __call($name, $args) {
       # Try catch in here...
    }
}

class Foo extends FooAbstract {
   public function hi() {
     # Code with try catch...
   }
}

我如何在 Ruby 类中使​​用 __call 方法？？？