所以我自己尝试了12天的圣诞节编码.我还没有完成歌词,我还在努力弄明白.但我不明白为什么我的圣诞节"第一天"加倍并与另一份礼物合作,并且在第12天,没有礼物出现.我检查了我的开关盒,他们似乎是对的.是否有可能减少我的代码打印出完整的歌词?
#include <stdio.h>
#include <conio.h>
int main() // Main Function
{
int days, counter, num;
//int counter = 1;
printf("\t\t***TWELVE DAYS OF CHRISTMAS***\n");
printf("\t\t______________________________\n\n\n");
for (counter=0; counter<=12; counter++)
{
// counter++;
switch(counter)
{
case 1: printf("\t\tA Partridge in a Pear Tree\n");break; // Day 12
case 2: printf("\t\tTwo Turtle Doves\n"); break;
case 3: printf("\t\tThree French Hens\n"); break;
case 4: printf("\t\tFour Calling Birds \n"); break;
case 5: printf("\t\tFive Golden Rings\n"); break;
case 6: printf("\t\tSix Geese a Laying\n"); break;
case 7: printf("\t\tSeven Swans …Run Code Online (Sandbox Code Playgroud)