失败安全迭代器是那些没有失败的迭代器throw ConcurrentModificationException.
但是fail safe iterators和之间有什么区别weakly consistent iterators?
两者都一样吗?
我目前正在观看视频教程,我对这段代码感到非常困惑:
public static boolean insert(Member mbr) throws Exception {
String SQL = "INSERT INTO test (first_name, last_name) " +
"VALUES (?, ?)";
ResultSet keys = null;
try (
Connection con = DBUtil.getConnection(DBType.MYSQL);
PreparedStatement stmt = con.prepareStatement(SQL, Statement.RETURN_GENERATED_KEYS);
) {
stmt.setString(1, mbr.getFname());
stmt.setString(2, mbr.getLname());
int affected = stmt.executeUpdate();
if (affected == 1) {
keys = stmt.getGeneratedKeys();
keys.next();
int newKey = keys.getInt(1);
mbr.setMemberid(newKey);
} else {
System.err.println("No rows affected");
return false;
}
} finally {
if (keys != null) keys.close();
}
return …Run Code Online (Sandbox Code Playgroud) 我想实现char* removeChars(char* str, char* remove)的C
但是,如果我通过"Battle of the Vowels"和"aeiou",我得到"Bttlftwl"恢复.任何帮助指出我的代码中的错误将不胜感激!准备即将到来的采访!请注意,这是一个来自编程访谈暴露的问题,提供的解决方案是在C#中,我正在尝试实现C版本以及练习.
char* removeCharacters(char* string, char* toRemove)
{
int flags[128];
while(*toRemove)
{
flags[*toRemove] = 1;
toRemove++;
}
char* head = string;
char* src = string;
char* dest = string;
while(*string)
{
if (!flags[*string])
{
*dest = *src;
dest++;
}
src++;
string++;
}
*dest = NULL;
return head;
}
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