如何反转最后一位int?
int a = 11;
System.out.print(a + " " + Integer.toBinaryString(a)) //11 1011
int b = invertLastBit(a);
System.out.print(b + " " + Integer.toBinaryString(b)); //10 1010
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我写了这个:
static int invertLastBit(int i)
{
String s = Integer.toBinaryString(i);
if (s.charAt(s.length()-1) == '0'){
s = s.substring(0,s.length() - 1);
s = s+"1";
}else if (s.charAt(s.length()-1) == '1') {
s = s.substring(0, s.length() - 1);
s = s + "0";
}
return Integer.parseInt(s, 2);
}
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但是我该如何重写invertLastBit()呢?