小编Aid*_*dis的帖子

我正在尝试构建/更新字典.我有昵称作为temp_dict中的键,并寻找要添加的ID.

摘录自我的代码.我认为这足以让你看到我的错误.

d1 = {u'status': u'ok', u'count': 1, u'data': [{u'nickname': u'45sss', u'account_id': 553472}]}


   temp_dict = {}
   for key, value in d1.iteritems():
        if "data" == key:
            for dic2 in value:
                  x = dic2['nickname']
                  y = dic2['account_id']
                  temp_dict[x] = y;

我的错误:

Traceback (most recent call last):
File "untitled.py", line 36, in <module>
get_PlayerIds_Names_WowpApi_TJ_() #Easy going. Some issues with case letters.
File "g:\Desktop\Programming\WOWP API\functions.py", line 44, in get_PlayerIds_Names_WowpApi_TJ_
check_missing_player_ids(basket)
File "g:\Desktop\Programming\WOWP API\functions.py", line 195, in check_missing_player_ids
temp_dict[x] = y;
TypeError: 'unicode' object does …

我试图从嵌套字典(从json加载)收集信息.我试图用for循环来做到这一点.我无法在字典中找到一个名为"players"的词典."玩家"包含带有玩家姓名及其ID的字典.我想提取那本字典.您可以在下面找到我的代码和数据样本.

我能够通过第一级迭代到字典,但我无法过滤掉更深层次.

我一直在寻找其他类似的问题,但他们正在解决字典迭代的不同问题.我无法将它们用于我的目的.我正在考虑使用data.keys()["players"]来提取我需要的信息,但我现在无法解决这个问题.

for key, value in dct.iteritems():
    if value == "players":
        for key, value in dct.iteritems():
            print key, value

我的数据样本:

{
"[CA1]": {
    "team_tag": "[CA1]",
    "team_name": "CzechAir",
    "team_captain": "MatejCzE",
    "players": {
        "PeatCZ": "",
        "MartyJameson": "",
        "MidnightMaximus": "",
        "vlak_in": "",
        "DareD3v1l": "",
        "Hugozhor78": ""
    }
},
"[GWDYC]": {
    "team_tag": "[GWDYC]",
    "team_name": "Guys Who Dated Your Cousin",
    "team_captain": "Teky1792",
    "players": {
        "wondy22": "",
        "dzavo1221": "",
        "Oremuss": "",
        "Straker741": "",
        "Vasek9266": ""
    }
}
}

我想玩现在以JSON格式保存的数据.但我对R来说很新,并且对如何使用数据几乎没有任何线索.你可以在下面看到我设法实现的目标.但首先,我的代码:

library(rjson)
json_file <- "C:\\Users\\Saonkfas\\Desktop\\WOWPAPI\\wowpfinaljson.json"
json_data <- fromJSON(paste(readLines(json_file), collapse=""))

我能够获得数据:

for (x in json_data){print (x)}

虽然输出看起来很原始:

[[1]]
[[1]]$wins
[1] "118"

[[1]]$losses
[1] "40"
# And so on

请注意,JSON有点嵌套.我可以使用Python创建表,但R看起来要复杂得多.

编辑:

我的JSON:

{
"play1": [
    {
        "wins": "118",
        "losses": "40",
        "max_killed": "7",
        "battles": "158",
        "plane_id": "4401",
        "max_ground_object_destroyed": "3"
    },
    {
        "wins": "100",
        "losses": "58",
        "max_killed": "7",
        "battles": "158",
        "plane_id": "2401",
        "max_ground_object_destroyed": "3"
    },
    {
        "wins": "120",
        "losses": "38",
        "max_killed": "7",
        "battles": "158",
        "plane_id": "2403",
        "max_ground_object_destroyed": "3"
    }
],

"play2": [
    {
        "wins": …

获得有向图的所有边对的最佳方法是什么.我只需要那些方向相反的边缘.我需要用它来比较关系的对称性.

我寻求以下结果(虽然我不确定是获得结果的最佳形式)输入:

[(a,b,{'weight':13}),
 (b,a,{'weight':5}),
 (b,c,{'weight':8}),
 (c,b,{'weight':6}),

 (c,d,{'weight':3}), 
 (c,e,{'weight':5})] #Last two should not appear in output because they do not have inverse edge.

输出:

[set(a,b):[13,5], 
 set(b,c):[8,6]] 

这里的序列是导入的,因为它告诉了方向.

我该怎么看？

我想解析JSON.如果我在一行中编写JSON就可以了

json_input = '{ "rate_of_climbing": 18.4, "speed_factor": 520}'

但是如果我有JSON格式化,那么解析器不起作用:

json_input = '{ 
    "rate_of_climbing": 18.4, 
    "speed_factor": 520
}'

如何获取JSON以读取格式化字符串？

我的完整代码:

import json
json_input = '{ 
    "rate_of_climbing": 18.4, 
    "speed_factor": 520
}'

try:
    decoded = json.loads(json_input)

    print json.dumps(decoded, sort_keys=True, indent=4)
    print "JSON parsing example: ", decoded['rate_of_climbing']
    print "Complex JSON parsing example: ", decoded['speed_factor']

except (ValueError, KeyError, TypeError):
    print "JSON format error"

如何将utf-8字符写入csv文件？

我的数据和代码:

# -*- coding: utf-8 -*-

l1 = ["žžž", "???"]
l2 = ["žžž", "???"]

thelist = [l1, l2]

import csv
import codecs

with codecs.open('test', 'w', "utf-8-sig") as f:
   writer = csv.writer(f)
   for x in thelist:
       print x
       for mem in x:
           writer.writerow(mem) 

错误消息:

Traceback (most recent call last):
   File "2010rudeni priimti.py", line 263, in <module>
writer.writerow(mem)
 File "C:\Python27\lib\codecs.py", line 691, in write
return self.writer.write(data)
 File "C:\Python27\lib\codecs.py", line 351, in write
data, consumed = self.encode(object, self.errors)
 File "C:\Python27\lib\encodings\utf_8_sig.py", line 82, …

我现在有这个数据:

animal   age             count
dogs     1               49
         2              134
         3              147
         4              154
cats     1              189
         2              254
         3              259
         4              261

我想将年龄列转换为每个年龄段的4个年龄段:

animal   age1 age2 age3 age4 
dogs      49   134  147  154  
cats     ....................   

我已经尝试过df.T和df.transpose(),但它们都返回了原始列.

我有不同球员的统计数据.我想知道如何操纵我的数据.我怎么能找到:

• 具有最高"胜利"数的矩阵？
• 矩阵中最好"赢"到"损失"比率的线？

• 如何在三个矩阵的列中比较"胜利"的值？

  library(jsonlite)
  iris2 <- fromJSON("C:\\Users\\Saonkfas\\Desktop\\WOWPAPI\\wowpfinaljson.json")
  print(iris2)
  for (x in iris2){print (x)}
  

  Run Code Online (Sandbox Code Playgroud)

这是我打印后的内容:

   wins losses max_killed battles plane_id max_ground_object_destroyed
1  118     40          7     158     4401                           3
2  100     58          7     158     2401                           3
3  120     38          7     158     2403                           3
  wins losses max_killed battles plane_id max_ground_object_destroyed
1   12    450          7     158     4401                           3
2  150      8          7     158     2401                           3
3  120    328          7     158     2403                           3
  wins losses max_killed battles plane_id max_ground_object_destroyed
1  158     40          7     158 …