我在Angular 5.2.5应用程序中使用Angular-CLI 1.6.6和@ angular/service-worker 5.2.5.除了在我们的生产环境中弹出一条错误消息外,一切在本地lite-server和生产服务器上都能正常工作:
Failed to load resource: the server responded with a status of 504 (Gateway Timeout)
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查看ngsw-worker.js脚本,我发现上面生成错误消息的行(2466):
async safeFetch(req) {
try {
return await this.scope.fetch(req);
}
catch (err) {
this.debugger.log(err, `Driver.fetch(${req.url})`);
return this.adapter.newResponse(null, {
status: 504,
statusText: 'Gateway Timeout',
});
}
}
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catch中的控制台日志记录错误会发出以下错误:
TypeError: Failed to execute 'fetch' on 'ServiceWorkerGlobalScope': 'only-if-cached' can be set only with 'same-origin' mode
at Driver.safeFetch (ngsw-worker.js:2464)
at Driver.handleFetch (ngsw-worker.js:1954)
at <anonymous>
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与此问题相关的错误:导致'ServiceWorkerGlobalScope'上执行'fetch'失败的原因:'only-if-cached'只能设置为'same-origin'模式错误?
生成此错误的req是应用程序的任何首次访问:
https://example.com/test/#/connect
https://example.com/test/#/map?token=[accestoken]
...
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在应用程序重新加载时,错误不会重复.
有人可以帮帮我吗?服务工作者的safeFetch()中是否存在错误(可能支持HashLocationStrategy)?我必须在配置中更改任何内容吗?
service-worker angular-cli angular angular5 angular-service-worker
我有一个简单的服务人员,将两个资源(index.html,app.js)添加到缓存(在安装时),删除旧的缓存(在激活时),并从缓存中提供资源(如果存在),从网络(在网络上)提供资源取)。为了注册新的服务工作者并删除旧的缓存,我为CACHE_NAME中的每个新资源版本增加了版本号:
var CACHE_NAME = 'test-cache-v4';
var urlsToCache = ['./','./app.js'];
self.addEventListener('install', function (event) {
event.waitUntil(
caches.open(CACHE_NAME)
.then(function (cache) {
console.log('Opened cache');
return cache.addAll(urlsToCache);
})
);
return self.skipWaiting();
});
self.addEventListener('activate', function(event) {
event.waitUntil(
caches.keys().then(function(keyList) {
return Promise.all(keyList.map(function(key) {
if (key !== CACHE_NAME) {
return caches.delete(key);
}
}));
})
);
});
self.addEventListener('fetch', function(event) {
event.respondWith(
caches.open(CACHE_NAME).then(function(cache){
return cache.match(event.request)
.then(function(response) {
if (response) {
console.log('SERVED FROM CACHE');
return response;
}
return fetch(event.request).then(function(response){
console.log('Response from network is:', response);
return response;
});
}
)
})
); …Run Code Online (Sandbox Code Playgroud)