小编Che*_* Ju的帖子

我目前正在使用Django Rest Framwork处理Django.

我无法在嵌套对象字段中更新我的对象.

serializer.py

class OwnerSerializer(serializers.ModelSerializer):
    class Meta:
        model =  Owner
        fields = ('id', 'name')

class CarSerializer(serializers.ModelSerializer):
    owner = ownerSerializer(many=False, read_only=False) 
    class Meta:
        model =  Car
        fields = ('id', 'name', 'owner')

view.py

class OwnerViewSet(viewsets.ModelViewSet):
    queryset = Owner.objects.all()
    serializer_class = OwnerSerializer

class CarViewSet(viewsets.ModelViewSet):
    serializer_class = CarSerializer
    queryset = Car.objects.all()

    def create(self, request):
        serialized = self.serializer_class(data=request.DATA)
        if serialized.is_valid():
            serialized.save()
            return Response(status=HTTP_202_ACCEPTED)
        else:
            return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

当我这样做:

Request URL:http://localhost:9000/api/v1/cars/1/?format=json
Request Method:PUT
Request Paylod :
{
    "id":1,
    "name": "TEST", 
    "ower": {
        "id":1,
        "name": …

与此主题相关

嗨,我不能按照附件中的答案,因为序列化后缺少ID.

• Model.py

class Owner(models.Model):
    name = models.CharField(db_index=True, max_length=200)

class Car(models.Model):
    name = models.CharField(db_index=True, max_length=200)
    LCVS  = models.ForeignKey(Owner)

• View.py

class OwnerViewSet(viewsets.ModelViewSet):
    queryset = Owner.objects.all()
    serializer_class = OwnerSerializer

class CarViewSet(viewsets.ModelViewSet):
    serializer_class = CarSerializer
    queryset = Car.objects.all()

• Serializer.py

class OwnerSerializer(serializers.ModelSerializer):
    class Meta:
        model =  Owner
        fields = ('id', 'name')

class CarSerializer(serializers.ModelSerializer):
    owner = OwnerSerializer() 

    class Meta:
        model =  Car
        fields = ('id', 'name', 'owner')

    def create(self, validated_data):
        tmp_owner = Owner.objects.get(id=validated_data["car"]["id"])
        car = Car.objects.create(name=self.data['name'],owner=tmp_owner)
        return car

现在我发送以下请求:

Request URL:http://localhost:9000/api/v1/cars
Request Method:POST …

是否可以使用Oledb将数据写入常见的Excel？

没有表结构或任何东西,它是用户文档.

当我尝试时,我总是有一个OleDbException

• "INSERT"查询回复:操作必须使用可以更新的应用程序.
• "UPDATE"查询回复:没有给出一个或多个必需参数的值.

我的代码:

  using (OleDbConnection connection = new OleDbConnection(@"Provider=Microsoft.ACE.OLEDB.12.0;Data Source=" + @"C:\Users\[...]\Classeur.xls" + ";Extended Properties=\"Excel 8.0;HDR=NO;IMEX=1;READONLY=FALSE\""))
        {
            connection.Open();
            OleDbCommand commande = new OleDbCommand(
              "INSERT INTO [Feuil1$](F1,F2,F3) VALUES ('A3','B3','C3');", connection);
            commande.ExecuteNonQuery();

            connection.Close();
            connection.Dispose();
        }

新测试(没有成功!):

       using (OleDbConnection connection = new OleDbConnection(@"Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + @"C:\Users\[...]\Classeur.xls" + ";Extended Properties=\"Excel 8.0;HDR=NO;IMEX=1;READONLY=FALSE\""))
        {
            string column = "A";
            string row = "1";
            string worksheetName = "Feuil1";
            string data = "TEST";
            connection.Open();
            string commandString = String.Format("UPDATE [{0}${1}{2}:{1}{2}] SET F1='{3}'", worksheetName, column, row, data);
            OleDbCommand …