小编axt*_*scz的帖子

所以我有一个包含地图片段的空片段.每当我尝试激活包含地图的片段时,我的应用程序崩溃并在此行返回空指针错误:

map = ((MapFragment) getFragmentManager().findFragmentById(R.id.map))
                .getMap();

完整错误消息:

java.lang.NullPointerException: Attempt to invoke virtual method 'com.google.android.gms.maps.GoogleMap com.google.android.gms.maps.MapFragment.getMap()' on a null object reference
            at com.collusion.serviceassistant.ReturnVisitDetails.onViewCreated(ReturnVisitDetails.java:39)
            at android.app.FragmentManagerImpl.moveToState(FragmentManager.java:904)
            at android.app.FragmentManagerImpl.moveToState(FragmentManager.java:1062)
            at android.app.BackStackRecord.run(BackStackRecord.java:684)
            at android.app.FragmentManagerImpl.execPendingActions(FragmentManager.java:1447)
            at android.app.FragmentManagerImpl$1.run(FragmentManager.java:443)
            at android.os.Handler.handleCallback(Handler.java:733)
            at android.os.Handler.dispatchMessage(Handler.java:95)
            at android.os.Looper.loop(Looper.java:136)
            at android.app.ActivityThread.main(ActivityThread.java:5001)
            at java.lang.reflect.Method.invoke(Native Method)
            at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:785)
            at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:601)

这是我的片段代码:

import android.app.Activity;
import android.app.Dialog;
import android.net.Uri;
import android.os.Bundle;
import android.app.Fragment;
import android.util.Log;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;

import com.google.android.gms.common.ConnectionResult;
import com.google.android.gms.common.GooglePlayServicesUtil;
import com.google.android.gms.maps.CameraUpdateFactory;
import com.google.android.gms.maps.GoogleMap;
import com.google.android.gms.maps.MapFragment;
import com.google.android.gms.maps.MapView;
import com.google.android.gms.maps.model.BitmapDescriptorFactory; …

所以我尝试使用Android Studio的新版本3从头开始一个新项目.一切都有效,直到它试图建立项目.然后我收到此错误消息:

Error:Unable to find method 'org.gradle.tooling.model.gradle.GradleBuild.getIncludedBuilds()Lorg/gradle/tooling/model/DomainObjectSet;'.
Possible causes for this unexpected error include:<ul><li>Gradle's dependency cache may be corrupt (this sometimes occurs after a network connection timeout.)
<a href="syncProject">Re-download dependencies and sync project (requires network)</a></li><li>The state of a Gradle build process (daemon) may be corrupt. Stopping all Gradle daemons may solve this problem.
<a href="stopGradleDaemons">Stop Gradle build processes (requires restart)</a></li><li>Your project may be using a third-party plugin which is not compatible with the other plugins in the project or the …

所以我正在制作一个需要处理多个数组的程序.有没有办法对所有这些数组进行排序以反映一个数组的排序？这些值在所有三个数组中处于相同的索引位置,并且在排序后需要保持相同的索引值

例:

我有三个数组:

String[] distance = [1,3,6,7,9];
String[] name = [Joel, John, Joe, Jill, Jane]
String[] values = [1.5,2.3,5.6,7.1,6.5];

有没有办法对距离数组进行排序,然后将该排序反映到其他数组.因此,如果我按名称排序并且Jane变为0,则其他数组中相同位置的其他值也将变为0.我怎么能这样做？

所以基本上我一直在使用Javascript开发一个小型的个人项目,我遇到了麻烦.我正在尝试使用Javascript从2D数组生成HTML列表.这是我的代码:

function generatePageFromArray(page, array){
var entry, i, j;
for (i = 0; i < array.length; ++i) {
    entry = array[i];
    for (j = 0; j < entry.length; j = j + 2) {
        page = page + '<tr>'+
                    '<td class="favoritesContainer"><input type="checkbox" class="favorites"></input></td>';
        page = page +  '<td class="english">' + entry[j,0] + '</td>';
        page = page +  '<td class="spanish">';
        if (entry[j,1].indexOf("|") > 0){
            var spanishTerms = entry[j,1].split("|");
            var strLength = spanishTerms.size;
            for (i = 0; i < strLength; i++){
                page = …