我在C#和Java中发现了一些奇怪的东西.我们来看看这个C++代码:
#include <iostream>
using namespace std;
class Simple
{
public:
static int f()
{
X = X + 10;
return 1;
}
static int X;
};
int Simple::X = 0;
int main() {
Simple::X += Simple::f();
printf("X = %d", Simple::X);
return 0;
}
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在控制台中,您将看到X = 11(在此处查看结果 - IdeOne C++).
现在让我们看一下C#上的相同代码:
class Program
{
static int x = 0;
static int f()
{
x = x + 10;
return 1;
}
public static void Main()
{
x += f(); …Run Code Online (Sandbox Code Playgroud) 我想将"account"参数应用于所有路径,没有任何例外.有没有办法用Swagger 2做这个(我不想为每个路径应用"account"参数)?
{
"swagger": "2.0",
"info": {
"version": "1.0",
"title": "Doc"
},
"host": "localhost",
"schemes": [
"http"
],
"produces": [
"application/json"
],
"parameters": {
"account": {
"in": "header",
"name": "X-ACCOUNT",
"description": "Account id",
"type": "string",
"required": true
}
},
"paths": {
"/account": {
"get": {
"summary": "Get account",
"operationId": "getAccount",
"responses": {
"200": {
"description": "test"
}
}
}
},
..... other paths
}
}
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public function index()
{
return
Model::select(['id', 'some_field', ...// more some fields])
->with('data') // load relation
->paginate(20);
}
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如何格式化(转换/操作)从数据库获取的数据?
CakePHP ORM对此有有用的方法 - https://book.cakephp.org/3.0/en/orm/query-builder.html#adding-calculated-fields && https://book.cakephp.org/3.0/en/ orm/retriving-data-and-resultsets.html#map-reduce
但我找不到任何东西可以帮助我在 Laravel 中做同样的事情。我可以覆盖模型中的“toArray”方法,但这会影响所有应用程序部分(不仅仅是控制器中的索引操作)。
大家好,我有双缓冲的问题.我不知道为什么,但我的文字不是绘图(没有双缓冲文本是绘图).
这是代码:
m_hDC = BeginPaint(m_hWnd, &m_ps);
m_graphics = new Graphics(m_hDC);
memDC = CreateCompatibleDC(m_hDC);
pMemGraphics = new Graphics(memDC);
pMemGraphics->DrawString(L"Hello world!", -1, font, PointF(100, 100), &brush);
BitBlt(m_hDC, 0, 0, 500, 200, memDC, 0, 0, SRCCOPY);
EndPaint(m_hWnd, &m_ps);
delete(pMemGraphics);
delete(m_graphics);
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怎么了?