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删除networkx DiGraph中的所有节点,其中度数和出度等于1

假设我在NetworkX中创建了一个DiGraph:

import networkx as nx

G = nx.DiGraph()

n = ["A","B","C","D","E","F","H","I","J","K","L","X","Y","Z"]

e = [("A","Z"),("Z","B"),("B","Y"),("Y","C"),("C","G"),("G","H"),("G","I"),("I","J"),("K","J"),("J","L"),("F","E"),("E","D"),("D","X"),("X","C")]

G.add_nodes_from(n)

G.add_edges_from(e)
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如何删除所有具有in-degree和out-degree等于1的节点,以便我的图形看起来像这样?:

import networkx as nx

G = nx.DiGraph()

n = ["A","C","F","G","H","J","K","L"]

e = [("A","C"),("C","G"),("G","H"),("G","J"),("K","J"),("J","L")

G.add_nodes_from(n)

G.add_edges_from(e)
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我们的想法是删除"流通"节点并保持连接.

python graph-theory networkx

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graph-theory ×1

networkx ×1

python ×1