我有UIViewController一个UIContainerView内部.根据某个条件是否为真,我想以编程方式将容器视图的嵌入视图设置为不同的视图UIViewController.我注意到你只能有一个嵌入segue来设置一个UIViewController,所以有没有办法完成这个?
我尝试将容器视图设置为插座,但我找不到任何设置嵌入式的方法UIViewController.任何关于如何开始这方面的建议将不胜感激.
在我的应用程序中,我需要将自定义User对象保存NSDictionary在中NSUserDefaults。我尝试使用以下代码进行此操作:
NSDictionary *userObjectDictionary = response[@"user"];
NSLog(@"USER OBJECT:\n%@", userObjectDictionary);
[defaults setObject:userObjectDictionary forKey:@"defaultUserObjectDictionary"];
[defaults synchronize];
Run Code Online (Sandbox Code Playgroud)
这种尝试使我的应用程序崩溃,并显示以下消息:
由于未捕获的异常“ NSInvalidArgumentException”而终止应用程序,原因:“试图插入非属性列表对象{type =不可变的dict,count = 10,条目=> 0:status_id = 1:{contents =“ first_name”} = exampleFirstName 3 :id = {值= +2,类型= kCFNumberSInt64Type} 4:{contents =“ profile_picture”} = {contents =“ http://myDevServer.com/pictures/userName.jpg ”} 5:last_name = exampleLastName 7:电子邮件= {contents =“ myEmail@gmail.com”}} 8:{contents =“ badge_count”} = {值= +0,类型= kCFNumberSInt64Type} 9:user_name =用户名10:{contents =“ phone_number”} = = {contents = “ 0123456789”} 12:{contents =“ status_updated_at”} =}用于键defaultUserObjectDictionary'
这是User我尝试保存它之前我的对象字典的样子:
{
"badge_count" = …Run Code Online (Sandbox Code Playgroud) 我刚开始Core Data在我的应用程序中学习和使用.每当我获取我保存的对象的列表时,我想确保我也删除已经Core Data存在超过一周的对象(显然我在测试时会更少).
我怎么做到这一点?这些模型对象默认情况下是否具有类似"createdAt"的属性,就像其他数据库提供"created_at"和"updated_at"等默认值一样?
如果没有,我正在考虑Date在我的数据模型中添加类型的"createdAt"属性,但是我仍然对如何删除超过一周的对象进行删除感到困惑Core Data.
任何帮助或建议将不胜感激,因为我仍然是使用这个强大工具的新手.谢谢.
我Spree Commerce从 GitHub 下载了 3.0.8 版本的代码,这样我就可以直接为我的学校项目自定义代码。根据此链接中的指示:
https://github.com/spree/spree/tree/v3.0.8
我运行了以下命令:
bundle install
bundle exec rake sandbox
cd sandbox
rails server
Run Code Online (Sandbox Code Playgroud)
然而,它没有像我最初使用 Spree 作为 gem 时那样的样本数据。如何在我的沙盒应用程序中获取相同的示例数据?
根据Bharat soni的回答,我尝试了以下方法:
bundle exec rake db:seed
Run Code Online (Sandbox Code Playgroud)
但是在运行第一个命令后,我收到以下“rake aborted”错误:
Rafi-MacBook-Air:sandbox rafi7$ bundle exec rake db:seed
loading ruby /Users/rafi7/Desktop/Schoolwork/Senior/Spring/CSC394/Medical Project/spree/core/db/default/spree/countries.rb
loading ruby /Users/rafi7/Desktop/Schoolwork/Senior/Spring/CSC394/Medical Project/spree/core/db/default/spree/default_reimbursement_type.rb
loading ruby /Users/rafi7/Desktop/Schoolwork/Senior/Spring/CSC394/Medical Project/spree/core/db/default/spree/roles.rb
loading ruby /Users/rafi7/Desktop/Schoolwork/Senior/Spring/CSC394/Medical Project/spree/core/db/default/spree/states.rb
loading ruby /Users/rafi7/Desktop/Schoolwork/Senior/Spring/CSC394/Medical Project/spree/core/db/default/spree/stores.rb
loading ruby /Users/rafi7/Desktop/Schoolwork/Senior/Spring/CSC394/Medical Project/spree/core/db/default/spree/zones.rb
rake aborted!
ActiveRecord::RecordInvalid: Validation failed: Name has already been taken
/Users/rafi7/.rvm/gems/ruby-2.3.0/gems/activerecord-4.2.6/lib/active_record/validations.rb:79:in `raise_record_invalid'
/Users/rafi7/.rvm/gems/ruby-2.3.0/gems/activerecord-4.2.6/lib/active_record/validations.rb:43:in `save!'
/Users/rafi7/.rvm/gems/ruby-2.3.0/gems/activerecord-4.2.6/lib/active_record/attribute_methods/dirty.rb:29:in `save!'
/Users/rafi7/.rvm/gems/ruby-2.3.0/gems/activerecord-4.2.6/lib/active_record/transactions.rb:291:in …Run Code Online (Sandbox Code Playgroud) 在我的Android应用程序中,当我从后端读取段落时,我想实现成功和错误回调.在iOS中,它看起来像这样:
在我的Passage.h中:
-(void)getPassagesWithSuccessCallback:(void (^)(NSArray<Passage *> *))success errorCallback:(void (^)(NSString *))errorString;
Run Code Online (Sandbox Code Playgroud)
在我的Passage.m中:
-(void)getPassagesWithSuccessCallback:(void (^)(NSArray<Passage *> *))success errorCallback:(void (^)(NSString *))errorString {
MyApiInterface* api = [MyApiInterface sharedInstance];
[api sendGetRequestTo:@"passages" successCallback:[Passage modelListCallback:success] errorCallback:error];
}
Run Code Online (Sandbox Code Playgroud)
在我的Android应用程序中,我正在使用Volley处理我的API请求,但我希望通过使用Passage.java类以及public static void获取段落的方法来进一步封装此API接口.像这样的东西:
public static void getPassagesForFirebaseUser(FirebaseUser user, Context context) {
final String url = URL_BASE + "/passages.json" + "?auth=" + user.getToken(false);
final JsonObjectRequest request = new JsonObjectRequest(Request.Method.GET, url, null, new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
// convert JSON into ArrayList<Passage> object
// pass …Run Code Online (Sandbox Code Playgroud)