我正在阅读 w3schools 的 ajax 教程，那个 url 真的让我很困扰。他们从哪里得到的？我复制了 w3schools 提供的 ajax 示例代码，但它不起作用。我认为这是因为那个 url (demo_get.asp).. 这是我从 w3schools 复制的代码。
<!DOCTYPE html>
<html>
<head>
<script>
function loadXMLDoc()
{
var xmlhttp;
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("myDiv").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","demo_get.asp",true);
xmlhttp.send();
}
</script>
</head>
<body>
<h2>AJAX</h2>
<button type="button" onclick="loadXMLDoc()">Request data</button>
<div id="myDiv"></div>
</body>
</html>
我有一个ajax调用,它将表单中的数据发送到php文件,然后将该数据插入到数据库中.我打电话给die所说的php文件,因为我想尝试一些东西,但它不起作用.
<script>
$(document).ready(function () {
var $form = $('form');
$form.submit(function (event) {
event.preventDefault();
var formData = $form.serialize(),
url = $form.attr('action');
$.ajax({
type: "POST",
url: url,
data: formData,
success: function () {
//$("#div1").load("table.php");
alert('User Successfully Added');
document.getElementById("form1").reset();
}
});
});
});
</script>
这是php文件:
<?php
include('sqlconnection.php');
die('here');
$firstname = $_POST['fname'];
$lastname = $_POST['lname'];
$middlename = $_POST['mname'];
$password = $_POST['pword'];
$username = $_POST['uname'];
$gender = $_POST['gender'];
$utype = $_POST['utype'];
$query = "INSERT INTO user (firstname,lastname,middlename,gender) VALUES ('$firstname','$lastname','$middlename','$gender')";
mysqli_query($con,$query);
$result …