小编Tre*_*vor的帖子

#!/usr/bin/env python
import socket
clientsocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
clientsocket.connect(('192.168.1.123', 5162))
clientsocket.send('getval.1')
clientsocket.close
clientsocket.bind(('192.168.1.124', 5163))
clientsocket.listen(1)
while True:
    connection, address=clientsocket.accept()
    value=connection.recv(1024)
    print value

我试图让 python 向服务器发送消息，作为回报，服务器做出响应。然而，当我执行这段代码时，它给了我

Socket.error: [Errno 10022] An invalid argument was supplied