小编whe*_*SQL的帖子

没有这样的模块'FBSDKCoreKit'XCODE 7.4

我正在尝试使用FBSDKCoreKit和添加Facebook登录功能FBSDKLogin.当我尝试将这两个框架导入我的AppDelegate文件时,它显示错误

"没有这样的模块'FBSDKCoreKit'".

我改变Allow Non-modular Includes In Framework ModulesNOYES,但错误依然存在.

我需要帮助来提出解决方案以解决错误.

ios facebook-sdk-4.0 swift xcode7-beta4

8
推荐指数
3
解决办法
1万
查看次数

在循环中使用StreamWriter时出现“ Stream not Writable”错误

我试图用C#编写工具来帮助QA一些网络问题,并且遇到了问题。该程序应该每秒发送JSON格式的查询到服务器。

目前,它只能运行一次,但是在第二次尝试发送查询时,我遇到了一个异常,因为

“流不可写。”

这是我的代码:

public partial class Form1 : Form
{
    Timer timer1;
    String query;
    String result;

    HttpWebRequest request;
    StreamWriter writeData;
    StreamReader readData;
    HttpWebResponse response;


    public Form1()
    {
        InitializeComponent();
        timer1 = new Timer();
        timer1.Tick += new EventHandler(timer1_Tick);
        timer1.Interval = 1000;
        File.Delete(AppDomain.CurrentDomain.BaseDirectory + "log.txt");
        logOutput.ReadOnly = true;
        request = (HttpWebRequest)WebRequest.Create("a URL goes here");
        request.ContentType = "application/json";
        request.Method = "POST";
        query = "{some json stuff goes here}";
    }

    private void startButton_Click(object sender, EventArgs e)
    {
        if (!timer1.Enabled)
        {
            timer1.Start();
            startButton.Text = "Stop"; …
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c# json streamwriter

5
推荐指数
1
解决办法
5213
查看次数

方法getText()必须从UI线程(Android Studio)调用

我正在尝试为应用程序创建登录.但是我有一个问题.

这是我的代码:

package com.forgetmenot.loginregister;


import java.util.ArrayList;
import java.util.List;

import org.apache.http.NameValuePair;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

import android.app.Activity;
import android.content.Intent;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Log;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;

public class MainActivity extends Activity {
    EditText uname, password;
    Button submit;
    // Creating JSON Parser object
    JSONParser jParser = new JSONParser();
    private static final String TAG = "Login";

    JSONObject json;
    private static String url_login = "http://localhost:8080/ForgetMeNotApplication/Login";
   //JSONArray incoming_msg = null;
   @Override
   protected …
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java android gettext

3
推荐指数
1
解决办法
3万
查看次数

将2个面板并排对齐

我需要并排排列三个面板,我无法做到.

我尝试使用float:left但是没有用.

有人可以指点我正确的方向吗?

  <div class="panel panel-default" style="height:350px;width:400px;">
  <div class="panel-heading"> 1</div>
  <div class="panel-body">
  <div class="row">
  <div col="col-md-4" >
  <div class="panel-body"><img src="mb3.jpg" alt="cannot load image" `enter code here`class="img-responsive" />
  <button type="button" class="btn btn-primary btn-block">button</button>    </div>
  </div>
  <br>
  <br>
  <div col="col-md-4" >
  <div style="float:left;">
  <div class="panel panel-default" style="height:350px;width:400px;">
  <div class="panel-heading"> 2</div>
  <div class="panel-body">
  <div class="panel-body"><img src="mb4.png" alt="cannot load image"class="img-responsive"/>
  <button type="button" class="btn btn-primary btn-block">button</button>
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twitter-bootstrap-3

3
推荐指数
1
解决办法
2万
查看次数

MySQL GROUP_CONCAT()对所有行进行分组

我有以下查询:

select card.id as id, photo.image as photo
from card
left outer join card_image as photo on (photo.card=card.id)
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返回

+----+-------+
| id | photo |
+----+-------+
|  1 |     2 |
|  1 |     3 |
|  1 |     4 |
|  2 |     5 |
|  2 |     6 |
+----+-------+
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如果我改为photo.image as photo,group_concat(photo.image) as photos我得到以下结果

+----+---------------+
| id | photo         |
+----+---------------+
|  1 |     2,3,4,5,6 |
+----+---------------+
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但我的期望是

+----+-----------+
| id | photo …
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mysql sql

3
推荐指数
1
解决办法
2042
查看次数

TypeError - 无法隐式地将'int'对象转换为str

当我运行这段代码时,shell会输出错误'无法将'int'对象转换为str隐式'.

我在StackOverflow上尝试了其他修复,但是我无法在代码中解决问题.

import math
while True: 
    try:
        di = input('Input 7 digit number ')
        total = (int(di[0])+int(di[2])+int(di[4])+int(di[6]))*3+(int(di[1])+int(di[3])+int(di[5]))
    if len(str(di)) != 7:
        print('Incorrect')           
    if len(str(di)) == 7:
        print('Okay')
        multiplier = [3,1]
        times = ''
        total = 0     
        for index, digit in enumerate(list(str(di))):            
            total = total + int(digit)*multiplier[index%2]               
            times = times+str(int(digit)*multiplier[index%2])+', '          
        mof10 = total + (10 - total%10)          
        checkdigit = mof10 - total
        final = str(di) + str(checkdigit)
        print(times[:-1]) 
        print(total)
        print(mof10)
        print(checkdigit)
        print(final)
    final = (di[1]+di[3]+di[5])+((di[0]+di[2]+di[4]+di[6])*3)
    final = (final+4)
    Base10=(int(round(final, -1))) …
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python python-3.x

2
推荐指数
1
解决办法
2155
查看次数