这是一个摇滚,纸张,剪刀游戏.我的问题是,如果我私下移动武器.长度随机r =新随机(武器.长度); 它会给我一个错误.如果我在方法中移动了weapon.length,它将成功运行.有什么不同？
public class Game {
private String[] weapons = {"rock", "paper", "scissor"};
private Random r = new Random(weapons.length);
public void thePick() {
System.out.println(weapons[r.nextInt()]);
}
}
VS
public class Game {
private String[] weapons = {"rock", "paper", "scissor"};
private Random r = new Random();
public void thePick() {
System.out.println(weapons[r.nextInt(weapons.length)]);
}
}
这段代码的主要目标是使用这个关键字并设置全局变量(十,零,二十等于int 10,int 0,int 20.)那么我会调用该方法,它会将它们加在一起. (总价值30)
package javaapplication53;
public class NewClass {
public int ten = 10;
public int zero = 0;
public int twenty = 20;
public int yourMethod(int ten, int zero, int twenty) {
this.ten = ten;
this.zero = zero;
this.twenty = twenty;
return(ten +zero+ twenty);
}
}
然后我在main方法中调用了构造函数.
package javaapplication53;
public class JavaApplication53 {
public static void main(String[] args) {
NewClass nc = new NewClass();
nc.NewClass(ten, zero, twenty);
}
}
它说我必须输入3 int,我以为我在其他类中做了.
我是计算机编程的新手
这是代码:
基本上,这个代码打印出52张西装+等级的牌.
package javaapplication52;
public class JavaApplication52 {
public static void deck() {
String[] suit = { "Clubs", "Diamonds", "Hearts", "Spades" };
String[] rank = { "2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack",
"Queen", "King", "Ace" };
// avoid hardwired constants
int SUITS = suit.length;
int RANKS = rank.length;
int N = SUITS * RANKS;
// initialize deck
String[] deck = new String[N];
for (int i = 0; i < RANKS; i++) {
for (int j = …