有没有办法完全禁用Summernote中的图像上传,但保持图像网址输入?我发现最接近的是disableDragAndDrop: true选项,但这不会从图像弹出窗口中删除上传按钮
在express中使用以下POST功能.(我使用快递3.5.1)
app.post('/example', someFunctionOne, someFunctionTwo, function(req, res){
if(!req.someVar){
return res.send(400, { message: 'error'});
} else{
return res.json(200, { message: 'ok'});
}
});
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如果我从someFunctionOne得到一些结果,这意味着someFunctionTwo是多余的,有没有办法跳过someFunctionTwo并转到最后一个未命名的函数,它将发送响应?
所以我想以同样的方式存在"next()"函数,其中是"last()"函数?如果这不可能,为什么不呢?这似乎是对我的疏忽,但有充分的理由吗?
这是我用来动态创建图表的代码Virtual Basic:
Dim Chart As Object
Set Chart = Charts.Add
With Chart
If bIssetSourceChart Then
CopySourceChart
.Paste Type:=xlFormats
End If
For Each s In .SeriesCollection
s.Delete
Next s
.ChartType = xlColumnClustered
.Location Where:=xlLocationAsNewSheet, Name:=chartTitle
Sheets(chartTitle).Move After:=Sheets(Sheets.count)
With .SeriesCollection.NewSeries
If Val(Application.Version) >= 12 Then
.values = values
.XValues = columns
.Name = chartTitle
Else
.Select
Names.Add "_", columns
ExecuteExcel4Macro "series.columns(!_)"
Names.Add "_", values
ExecuteExcel4Macro "series.values(,!_)"
Names("_").Delete
End If
End With
End With
#The CopySourceChart Sub:
Sub CopySourceChart()
If Not …Run Code Online (Sandbox Code Playgroud) 我正在按照本教程讲解如何授权和从Web-api服务器获取承载令牌。通过fiddler在那里执行的任务非常简单,但是,当我尝试从控制台应用程序执行相同操作时,请求失败,并显示400 Bad Request Error。这是向服务器发出请求的代码:
var request = WebRequest.Create("http://localhost:12698/token") as HttpWebRequest;
request.Method = "POST";
request.ContentType = "application/x-www-form-urlencoded";
request.CookieContainer = new CookieContainer();
var authCredentials = "userName=" + user + "&password=" + password;
byte[] bytes = System.Text.Encoding.UTF8.GetBytes(authCredentials);
request.ContentLength = bytes.Length;
using (var requestStream = request.GetRequestStream()){
requestStream.Write(bytes, 0, bytes.Length);
}
using (var response = request.GetResponse() as HttpWebResponse){
authCookie = response.Cookies["access_token"];
}
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有人可以帮助我确定我在做什么错吗?还是我应该使用其他方法来获取身份验证令牌?
如何根据第一个元素或第二个或第三个元素搜索元组?
我知道如何搜索两个元组,但我怎么做两个以上呢?
type Stuff = (String, String, Int)
testStuff :: [Stuff]
testStuff = [
("beans","black",5),
("cod","fish",4),
("coke","diet",3)
]
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如何编写一个搜索"Stuff"并返回"int"值的函数?
例如,searchStuff"beans"应该返回5.
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