小编Rag*_*ram的帖子

调试eclipse插件项目 - PermGen空间,内存不足错误

我有一个插件项目.当我将其作为eclipse应用程序调试时,在打开的第二个eclipse中,我想打开Project explorer窗口.一旦我点击按钮执行此操作,我就会得到java.lang.OutOfMemoryError: PermGen space.我尝试在首选项中更改PermGen空间,但它没有帮助.任何人都可以建议一个解决方案.

eclipse eclipse-plugin

13
推荐指数
1
解决办法
1万
查看次数

是使用"Workspace project"maven存储库的任何方法吗?

我们有:Eclipse 3.6,Maven(M2Eclipse),两个项目(ProjectA和ProjectB)和pom.xml.

ProjectB依赖于ProjectA(使用maven).

  1. 如果我们将ProjectA安装到本地存储库(maven安装),ProjectB解决依赖关系确定.

  2. 如果我们不将ProjectA安装到本地存储库.在Maven POM编辑器中,我们将ProjectA添加为ProjectB的依赖项(M2Eclipse使用"工作区项目"存储库来解决此依赖关系).

好的,补充道.但是,如果我们做"maven包"或其他插件目标...依赖性没有解决.我们有这样的事情:

正在下载:http://repo1.maven.org/maven2/Artifact/ProjectA/maven-metadata.xml

当然,它无法解决.

现在是问题.构建ProjectB时如何使用"Workspace项目"?

PS为什么我不使用"maven install"?好的,它是100%的方法,但是当我做了很多小的改变时,它太长了做多余的操作.

PSS"工作区项目"我们可以看到Window - > Show View - > Maven Repositories.

eclipse m2eclipse maven

10
推荐指数
1
解决办法
6788
查看次数

Hudson构建失败:不可解析的父POM

我曾经和Hudson合作过我的项目,最近我不得不把它移到新的服务器上.

我配置它的方式完全相同(我可以告诉)但是当我尝试启动构建时,它失败了,我收到以下错误:

Démarré par l'utilisateur anonymous
Checking out http://[...]/trunk/MyProject/ear
A         .classpath
A         .project
A         target
AU        target/ear-1.0-SNAPSHOT.ear
A         target/application.xml
A         target/ear-1.0-SNAPSHOT
A         target/ear-1.0-SNAPSHOT/META-INF
A         target/ear-1.0-SNAPSHOT/META-INF/application.xml
AU        target/ear-1.0-SNAPSHOT/web-1.0-SNAPSHOT.war
AU        target/ear-1.0-SNAPSHOT/business-1.0-SNAPSHOT.jar
A         pom.xml
A         .settings
A         .settings/org.eclipse.jdt.core.prefs
A         .settings/org.maven.ide.eclipse.prefs
At revision 136
no change for http://[...]/trunk/MyProject/ear since the previous build
Found mavenVersion 3.0.2 from file jar:file:/usr/share/maven/apache-maven-3.0.2/lib/maven-core-3.0.2.jar!/META-INF/maven/org.apache.maven/maven-core/pom.properties
Parsing POMs
ERROR: Echec à la lecture des POMs
org.apache.maven.project.ProjectBuildingException: Some problems were encountered while processing the POMs:
[FATAL] Non-resolvable parent POM: Could not find artifact …
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hudson build parent pom.xml maven

8
推荐指数
1
解决办法
5万
查看次数

Jenkins:关于build.xml的路径

我在建立工作时得到了以下输出.我build.xml在我的项目的根目录中没有/var/lib/jenkins/jobs/mbp2/workspace/build.xml...我试图指定路径

> Invoke ant:
> 
> Target: /home/javier/programacion/mbp/myfirm2/build.xml
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但输出是一样的......

我是Jenkins的新手并且遵循了这个教程(所以我安装了这些插件,也许其中一个是错误的?).

Started by user anonymous
Checkout:workspace / /var/lib/jenkins/jobs/mbp2/workspace - hudson.remoting.LocalChannel@76996f0c
Using strategy: Default
Last Built Revision: Revision 9aafeea09cdb23317f2426f8209c75341565c070 (origin/HEAD, origin/master)
Checkout:workspace / /var/lib/jenkins/jobs/mbp2/workspace - hudson.remoting.LocalChannel@76996f0c
Fetching changes from 1 remote Git repository
Fetching upstream changes from file:///home/javier/programacion/mbp/myfirm
Seen branch in repository origin/HEAD
Seen branch in repository origin/master
Commencing build of Revision 9aafeea09cdb23317f2426f8209c75341565c070 (origin/HEAD, origin/master)
Checking out Revision 9aafeea09cdb23317f2426f8209c75341565c070 (origin/HEAD, origin/master)
Warning : There are multiple …
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jenkins

8
推荐指数
1
解决办法
2万
查看次数

Spring安全角色前缀和自定义用户详细信息服务

如何""在Spring中使用自定义用户详细信息服务设置角色前缀?

    <beans:bean id="authService" class="com.cisco.badges.business.services.AuthenticationService"/>

<authentication-manager>
        <authentication-provider user-service-ref="authService">
            <password-encoder ref="passwordEncoder">
                <salt-source ref="saltSource" />
            </password-encoder>
        </authentication-provider>
    </authentication-manager>
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@Service("authService")
public class AuthenticationService extends BaseService implements UserDetailsService, IAuthenticationService {

    @Autowired
    IUserRepository userRepository;

    @Autowired
    IAuthorityRepository authorityRepository;

    public AuthenticationService() {

    }

    public UserDetails loadUserByUsername(String username)
            throws UsernameNotFoundException {

        User user = userRepository.findByUsername(username);

        if(user == null)
            throw new UsernameNotFoundException("No user with username '" + username + "' found!");

        List<GrantedAuthority> authList = new ArrayList<GrantedAuthority>();

        for (Role role : user.getRoles()) {
            authList.add(new GrantedAuthorityImpl(role.getName()));
        }

        UserAuthentication userAuthentication = …
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roles spring-security security-roles

3
推荐指数
1
解决办法
9908
查看次数

基于日期的 SVN 标签

有人可以让我知道如何根据SVN中的某个日期制作标签或分支吗?

svn

2
推荐指数
1
解决办法
2450
查看次数

为什么我得到以下例外

这是我的nodefinder.java文件

package com.acme.web.action.executer;

import java.sql.ResultSet;
import java.util.Map;

import org.alfresco.web.bean.repository.Node;
import org.alfresco.web.bean.repository.Repository;
import org.alfresco.web.ui.common.component.UIActionLink;

import javax.faces.context.FacesContext;
import javax.faces.event.ActionEvent;

import org.alfresco.service.cmr.model.FileFolderService;
import org.alfresco.service.cmr.repository.NodeRef;
import org.alfresco.service.cmr.repository.NodeService;
import org.alfresco.service.cmr.repository.StoreRef;
import org.alfresco.service.cmr.search.SearchParameters;
import org.alfresco.service.cmr.search.SearchService;

public class NodeFinder {

    // private static final String = null;
    SearchParameters sp = new SearchParameters();
    private NodeService nodeService;
    private FileFolderService fileFolderService;
    //geting the filefolder service                     
    public FileFolderService getFileFolderService() {
        return fileFolderService;
    }
    // setting the file folder service 
    public void setFileFolderService(FileFolderService fileFolderService) {
        this.fileFolderService = fileFolderService;
    }
// getting the …
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java alfresco

0
推荐指数
1
解决办法
1223
查看次数