小编big*_*ata的帖子

如何在Unix中将分钟从unix时间戳转换为日期和时间.例如,时间戳1372339860对应于Thu, 27 Jun 2013 13:31:00 GMT.

我想转换1372339860为2013-06-27 13:31:00 GMT.

编辑:其实我希望它是根据美国时间GMT-4,所以它会2013-06-27 09:31:00.

如何从java中的日期获取月份:

        DateFormat inputDF  = new SimpleDateFormat("mm/dd/yy");
        Date date1 = inputDF.parse("9/30/11");

        Calendar cal = Calendar.getInstance();
        cal.setTime(date1);

        int month = cal.get(Calendar.MONTH);
        int day = cal.get(Calendar.DAY_OF_MONTH);
        int year = cal.get(Calendar.YEAR);

        System.out.println(month+" - "+day+" - "+year);

此代码返回日期和年份,但不是月份.

输出:

0 - 30 - 2011

如何使用格式的今天日期创建参数:

yyyy-mm-dd

在oozie.我将此变量传递给hive脚本,该脚本正在添加该日期的分区,我找到了使用以下命令创建时间戳的函数:

<param>DATE=${wf:timestamp()}</param>

应该以下列形式返回输出:

(YYYY-MM-DDThh:mm:ss.sZ). I.e.: 1997-07-16T19:20:30.45Z

但我收到错误:

No function is mapped to the name "wf:timestamp"

另外我只想YYYY-MM-DD从时间戳开始,并且没有子串函数也可以给我前10个字符串的字符串.

表格:

{{ Form::open(array('url' => 'user/create', 'files' => true)) }}

路线:

Route::resource('user', 'UserController');

UserController.php

  class UserController extends BaseController {

    public function index()
    {
        return 'hi11';
        //return View::make('home.index');
    }
    public function create()
    {
        return 'hi22';
        //return View::make('home.index');
    }

}

这段代码给出了
Symfony \ Component \ HttpKernel \ Exception \ MethodNotAllowedHttpException

我正在尝试从https://developers.google.com/analytics/solutions/articles/hello-analytics-api运行一个简单的示例来访问Google分析数据.

google-api-java-client-1.17.0-rc.zip从https://code.google.com/p/google-api-java-client/downloads/list下载了java api-library ,

示例代码显示编译错误:

    private static final HttpTransport HTTP_TRANSPORT = new NetHttpTransport();

    private static final JsonFactory JSON_FACTORY = new JacksonFactory();

    private static Analytics initializeAnalytics() throws Exception {
        Credential credential = OAuth2Native.authorize(
        HTTP_TRANSPORT, JSON_FACTORY, new LocalServerReceiver(),
        Arrays.asList(AnalyticsScopes.ANALYTICS_READONLY));

        Analytics analytics = Analytics.builder(HTTP_TRANSPORT, JSON_FACTORY)
  .setApplicationName("Hello-Analytics-API-Sample")
  .setHttpRequestInitializer(credential)
  .build();

我在类路径中添加了所有库,但是库似乎没有一些类:

OAuth2Native

AnalyticsScopes

Analytics

但这些课程都存在 http://code.google.com/p/google-api-java-client/source/browse/shared/shared-sample-cmdline/src/main/java/com/google/api/services/samples/shared/cmdline/oauth2/OAuth2Native.java?repo=samples&r=89662bd8ab341647b3f0aab8ed6a4fb444f478c2

我试图理解如果我将值重新分配给最终的数组元素会发生什么,这是代码:

public class XYZ {
    private static final String[] ABC = {"Hello"};

    public static void main(String[] args){
        System.out.println(ABC[0]);

        ABC[0] = " World!!!";
        System.out.println(ABC[0]);

    }
}

ABC是最终数组,并且在最初的位置它"Hello"最初有,但是当我重新分配它时," World!!!"它应该超过之前的值,或者它应该给出重新分配到最终变量的编译错误.这个程序运行正常,这是输出:

run:
Hello
 World!!!
BUILD SUCCESSFUL (total time: 0 seconds)

我在javascript中有一个数组,我想要一个元素的子数组,其元素位于位置n*3,n = 0,1,2 ..例如,如果:

var arr = [1,2,3,4,5,6,7,8,9,10,11,12]

var subArr = [1,4,7,10]

编辑:没有循环的任何soln.