小编And*_*son的帖子

我有一个文件夹结构

/com/cdy/ws/a.class files
/com/cdy/ws/b.class files
/com/cdy/ws/c.class files

当我运行以下命令"jar cvf asd.jar*.class"时,它给jar提供了所有类文件.但是没有生成文件夹结构.所有类文件都必须在"com.cdy/ws"下,但所有类都在META-INF的相同级别.谁能告诉我生成包结构的命令是什么？

谢谢

我正在尝试使用apache maven创建一个包.当我运行mvn clean install命令时,它给出了以下错误:

javax.servlet缺少dependencies.dependency.version':servlet-api.jar

我把'servlet-api.jar'放在我项目的资源文件夹中

任何人都可以告诉我应该在哪里放置该jar文件？

更新:这是我的pom.xml

    <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">

 <parent>
   <artifactId>felix-parent</artifactId>
   <groupId>org.apache.felix</groupId>
   <version>2.1</version>
   <relativePath>../pom/pom.xml</relativePath>
 </parent>

 <modelVersion>4.0.0</modelVersion>

 <artifactId>maven-bundle-plugin</artifactId>
 <version>2.4.1-SNAPSHOT</version>
 <packaging>maven-plugin</packaging>

 <name>Maven Bundle Plugin</name>
 <description>
  Provides a maven plugin that supports creating an OSGi bundle
  from the contents of the compilation classpath along with its
  resources and dependencies. Plus a zillion other features.
  The plugin uses the Bnd tool (http://www.aqute.biz/Code/Bnd)
 </description>

 <scm>
  <connection>scm:svn:http://svn.apache.org/repos/asf/felix/trunk/bundleplugin</connection>
  <developerConnection>scm:svn:https://svn.apache.org/repos/asf/felix/trunk/bundleplugin</developerConnection>
  <url>http://svn.apache.org/repos/asf/felix/trunk/bundleplugin</url>
 </scm>

 <build>
  <plugins>
   <plugin>
    <groupId>org.apache.maven.plugins</groupId>
    <artifactId>maven-compiler-plugin</artifactId>
    <configuration>
     <source>1.5</source>
     <target>1.5</target>
    </configuration>
   </plugin> …

我正在尝试使用maven-bundle-plugin创建一个包.该项目的pom.xml是:

    <project     xmlns="http://maven.apache.org/POM/4.0.0"
            xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
            xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">

    <modelVersion>4.0.0</modelVersion>
    <groupId>com.adobe.support.examples</groupId>
    <artifactId>com.adobe.support.examples.osgi.service</artifactId>
    <version>1.0.8</version>
    <packaging>bundle</packaging>
    <name>OSGi Service Example</name>
    <url>http://blogs.adobe.com/kmossman</url>
    <description>Adobe Developer Support OSGi Service Example</description>
    <!--  
    Credit: This example is based on Moritz Havelock's http://in-the-sling.blogspot.com/ 

    I suggest you use the most current versions of the plugin's. 
    Search the Central Repository for the most current versions http://search.maven.org/

    Use the search strings below and update the appropriate versions

    // Felix
    g:"org.apache.felix" a:"org.apache.felix.framework"
    g:"org.apache.felix" a:"maven-bundle-plugin"
    g:"org.apache.felix" a:"maven-scr-plugin"
    g:"org.apache.felix" a:"org.osgi.core"
    // Maven
    g:"org.apache.maven.plugins" a:"maven-compiler-plugin"  
    // Sling
    g:"org.apache.sling" a:"maven-sling-plugin" …

当我们有5个切换用例时，switch语句非常好，但是在我们的情况下，我们有15个切换用例。

我想知道什么是Java中switch语句的最佳替代选择

private OpwaardernId getOpwaardernId(String opId) {

    OpwaardernId opwaardernId;
    switch (opId) {
        case "ID001":
            opwaardernId = opwaardernId.of("xxx");
            break;
        case "ID002":
            opwaardernId = opwaardernId.of("123");
            break;
        case "ID002":
            opwaardernId = opwaardernId.of("abc");
            break;
        case "ID003":
            opwaardernId = opwaardernId.of("asd");
            break;
        case "ID004":
            opwaardernId = opwaardernId.of("rrr");
            break;
        case "ID005":
            opwaardernId = opwaardernId.of("ttt");
            break;
                ...
        case "ID015":
            opwaardernId = opwaardernId.of("aaa");
            break;

        default:
            opwaardernId = null;

    }
    return opwaardernId;
}

下面是我的 HTML 片段，

<div class="direct-service hide">
    ..   
    <input handle="input" type="hidden" name="./season" value="spring">
    <input handle="input" type="hidden" name="./season" value="">
    ...
</div>

我想迭代直接服务类中的所有元素并查找 . /season name 属性并检查该值是否为空。如果它是空的，我需要将元素修改为

<input handle="input" type="hidden" name="./season@Empty" value="">

我尝试使用以下代码获取基于值的名称属性

$("input[name='./season']").val();

但它给了我第一个元素的值，而不给我第二个元素。似乎我需要扫描 div 类中的所有元素。您能告诉我处理此案的最佳方法吗？