小编Har*_*eka的帖子

STL允许使用指向不同地图的迭代器擦除地图的键/值?

所以,我偶然发现的是:

std::map<double, int> map1;
std::map<double, int> map2;

map1[2.5] = 11;
map1[3.5] = 12;

map2[2.5] = 21;
map2[3.5] = 22;

std::map<double, int>::iterator iterMap1 = map1.find(2.5);

//I will now try to erase a key/value pair in map2 with an iterator 
//that points to map1. This is bad/wrong. But I am surprised 
//this is allowed. 
map2.erase(iterMap1); 

//what do you think would be printed?
print(map1);
print(map2);
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有人可以解释一下这种行为吗?我认为不应该允许这样做.

我得到的输出是:

Map1
2.5 11

Map2
2.5 21
3.5 22
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这对我来说没有意义.谢谢.

c++ stl stdmap erase

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