小编Luc*_*cky的帖子

#define N 20
int a[2N], i, *p, sum;

p = a;


/* p=a is equivalent to p = *a[0];
• p is assigned 300.
• Pointer arithmetic provides an alternative to array indexing.
• p=a; is equivalent to p=&a[=]; (p is assigned 300)

在这里,我没有得到如何p=*a[0]和p=&a[0]相同？*a[0]引用内存地址处的元素.