小编Col*_*ury的帖子

新的 Visual basic 程序员来了。试图让程序读取一个文本文件，但它似乎根本不起作用，没有错误消息或任何东西。它只是根本没有抓住价值

文本文件名完全相同。

Public Sub ReadDef()

    Dim DefSR As IO.StreamReader = IO.File.OpenText("BikeDefault.txt")

    GlobalTotBikes = DefSR.ReadLine()
    GlobalRentRate = DefSR.ReadLine()
    GlobalHSTRate = DefSR.ReadLine()
    GlobalTourRate = DefSR.ReadLine()
    GlobalGPSRate = DefSR.ReadLine()
    GlobalInsurRate = DefSR.ReadLine()
    GlobalWaterBotRate = DefSR.ReadLine()
    GlobalNextBookNum = DefSR.ReadLine()
    GlobalNextCustNum = DefSR.ReadLine()
    GlobalNextInvoiceNum = DefSR.ReadLine()

    DefSR.Close()

End Sub

我已经将此代码与给出的示例进行了多次比较，但没有发现任何不同。

谢谢。

它达到了必须打印线的程度System.out.printf("%4s%22s%24s\n","Year"...),然后在没有打印的情况下停止.

public class WorldPopulationGrowth {

    /**
     * @param args
     */
    public static void main(String[] args) {
        Scanner input = new Scanner( System.in);
        long BasePopulation; //The base, or current population
        double GrowthRate; //The rate of increase
        double GrowthResult; // The pop after growth rate increase

        //Time to obtain the numbers needed for Calculation
        //Specifically, the growth rate and the base population
        System.out.println("Welcome to the world population calculator");
        System.out.print("Enter the current world population:");
        BasePopulation = input.nextLong();
        System.out.println("Enter the current growth …

为我正在制作的项目创建了这个程序,但我似乎无法弄清楚为什么它从未在结果中给出任何1.我在这里踢自己因为它可能很简单.

为了清楚起见:程序必须滚动两个单独的模具36k次并显示结果.

import java.util.Random; //Going to need this

public class Dicerolling { //Start Class



public static void main( String[] args) 
{ //Start of Main
    Random randomNumbers = new Random(); // Generates random numbers
    int[] array = new int[ 13 ]; // Declares the array
    int dice1 = 0;
    int dice2;
    int total;

    //Roll the die 36,000 times
    for ( int roll = 1; roll <=36000; roll++ )
        dice1 = 1 + randomNumbers.nextInt ( 6 );
        dice2 = 1 + randomNumbers.nextInt …