小编Jor*_*sys的帖子

我正试图在Google Play报亭的文章库中添加几张图片但没有成功.我尝试添加3张尺寸合适的图片,但无法在文章库中显示.

<media:content url="[URL IMAGE]"
        type="image/png" expression="full" width="538" height="190">
  <media:description type="plain">[DESCRIPTION]</media:description>
  <media:credit role="author" scheme="urn:ebu">[AUTHOR]</media:credit>
</media:content>

这是我<item>元素的一个例子:

<item>
    <title><![CDATA[Arquean a cafetería]]></title>
    <link><![CDATA[http://google/wE-bacdkE]]></link>
    <content:encoded><![CDATA[Today we’re introducing a new age-based rating system for apps and games on Google Play. We know that people in different countries have different ideas about what content is appropriate for kids, teens and adults, so today’s announcement will help developers better label their apps for the right audience. Consistent with industry best practices, this change will …

我有一个Android应用程序,使用MediaPlayer该类播放来自Internet的流式音频.

当用户点击主页按钮运行其他应用程序时,如何让它继续在后台播放音频？

在运行其他应用程序时,我希望它继续播放音频.

我在用google-play-service-lib.如何更改Google地图的语言,即以korian语言或印地语显示位置.

我想通过蓝牙连接3台设备.

例如,我使用BluetoothChat.所以我理解我应该为这些设备使用不同的UUID.我一直试图通过这样的UUID = 766c82f0-e1b4-11df-85ca-0800200c9a66连接,我从Web UUID生成器得到它.但它根本不起作用.

如果我使用UUID = 00001101-0000-1000-8000-00805F9B34FB,我已成功连接(到1个设备)

我在哪里可以获得UUID？

我有一个javafx应用程序,用户在测试字段中输入一些细节,并在列表视图中显示.我现在有一个使用printjob打印的按钮,但每次按下打印按钮时,打印机都会打印垃圾数据,jhsjs6sh3#uhbsbkahi而不是ListView中的实际值.下面是我打印功能的代码

public void print (final Node node) {
        Printer printer = Printer.getDefaultPrinter();
        PageLayout pageLayout = printer.createPageLayout(Paper.A4, PageOrientation.PORTRAIT, Printer.MarginType.HARDWARE_MINIMUM);
        final double scaleX = pageLayout.getPrintableWidth() / node.getBoundsInParent().getWidth();
        final double scaleY = pageLayout.getPrintableHeight() / node.getBoundsInParent().getHeight();
        node.getTransforms().add(new Scale(scaleX, scaleY));

        PrinterJob job =PrinterJob.createPrinterJob();
        if (job != null ){

            boolean success = job.printPage(node);
            System.out.println("printed");
            if (success){
                System.out.println(success);
                job.endJob();
            }
        }

    }

@FXML ? private void printOps(ActionEvent event){? ? print(billingDataList);? 

}

我使用MacBook进行开发和HP打印机.

使用“ Cxense SDK for Android”，我收到重复类的消息：

Duplicate class android.support.v4.app.INotificationSideChannel found in modules classes.jar (**com.android.support:support-compat:27.1.1**) and classes.jar (**com.android.support:support-v4:22.2.0**)
Duplicate class android.support.v4.app.INotificationSideChannel$Stub found in modules classes.jar (com.android.support:support-compat:27.1.1) and classes.jar (com.android.support:support-v4:22.2.0) 
Duplicate class android.support.v4.app.INotificationSideChannel$Stub$Proxy found in modules classes.jar (com.android.support:support-compat:27.1.1) and classes.jar (com.android.support:support-v4:22.2.0) 
Duplicate class android.support.v4.app.ListFragment found in modules classes.jar (com.android.support:support-fragment:27.1.1) and classes.jar (com.android.support:support-v4:22.2.0) 
Duplicate class android.support.v4.app.ListFragment$1 found in modules classes.jar (com.android.support:support-fragment:27.1.1) and classes.jar (com.android.support:support-v4:22.2.0) 
Duplicate class android.support.v4.app.ListFragment$2 found in modules classes.jar (com.android.support:support-fragment:27.1.1) and classes.jar (com.android.support:support-v4:22.2.0) 
Duplicate class android.support.v4.app.LoaderManager found in modules classes.jar …

我已经通过非零退出值1,2,与multidex问题有关,但现在我得到非零退出值3.

工作室留言:

Information:Gradle: Executing tasks: [:emoticons_lib_proj:assembleDebug, :myProject_Developement:assembleDebug]
Information:5/27/2015 5:56 PM - Compilation completed with 1 error and 0 warnings in 5m 58s 77ms
Error:Gradle: Execution failed for task ':myProject_Developement:dexDebug'.

com.android.ide.common.process.ProcessException:org.gradle.process.internal.ExecException:进程'命令'C:\ Program Files\Java\jdk1.8.0_20\bin\java.exe''以非完成零退出值3

我希望有人可能已经面临这个问题而已经修复了.请让我知道我误导的地方,

此代码用于从其String表示生成XML文档.它在我的小单元测试中工作正常,但在我的实际xml数据中失败了.它触发的行是Document doc = db.parse(is);

有任何想法吗？

public static Document FromString(String xml)
{
    // from http://www.rgagnon.com/javadetails/java-0573.html
    try
    {
        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        DocumentBuilder db = dbf.newDocumentBuilder();
        InputSource is = new InputSource();
        is.setCharacterStream(new StringReader(xml));

        Document doc = db.parse(is);
        doc.normalize();

        return doc;
    }
    catch (Exception e)
    {
        Log.WriteError("Failed to parse XML", e, "XML.FromString(String)");
        return null;
    }
}

在Android中,我使用Service和MediaPlayer播放音乐.当我按下主页按钮时音乐继续播放,但如果我"轻扫"应用程序则会停止播放.

刷掉应用程序后我怎么能继续播放音乐？

我开发了一个应用程序,并注意到我在logcat中收到了很多"太多的属性引用"警告.

W/ResourceType? Too many attribute references, stopped at: 0x########

我使用support.v7.23.1.0也设计库.我定义我的样式如下:

 <style name="AppTheme.Description.TextView" parent="@android:style/Widget.TextView">
        <item name="android:textColor">@color/textColorSecondary</item>
        <item name="android:textColorPrimary">@color/textColorSecondary</item>
        <item name="android:textSize">@dimen/textSizeItemDescription</item>
    </style>

应用主题:

<!-- Base application theme. -->
<style name="AppTheme" parent="Theme.AppCompat.Light.NoActionBar">
    <!-- Customize your theme here. -->
    <item name="android:textColorHighlight">@color/colorPrimaryLight</item>
    <item name="colorPrimary">@color/colorPrimary</item>
    <!--status bar background color-->
    <item name="colorPrimaryDark">@color/colorPrimaryDark</item>
    <!-- color of drawer toggle and other stuff-->
    <item name="android:textColorSecondary">@color/textColorSecondary</item>
    <!-- Used to define what color preference categories titles will be-->
    <item name="colorAccent">@color/colorAccent</item>
    <!--overrides text color secondary for widgets and action mode     -->
    <item name="colorControlNormal">@color/colorControlNormal</item> …