我遇到了bind_param函数的问题.我将在下面发布所有信息.
错误:
Fatal error: Call to a member function bind_param() on a non-object in /home4/lunar/public_html/casino/blogpost.php on line 88
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MySQL错误:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ':user, :title, :message, :image, :category, NOW())' at line 1
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查询:
$user = $_COOKIE['user'];
$title = $_POST['title'];
$message = $_POST['message'];
$image = $_POST['image'];
$category = $_POST['category'];
$stmt = $mysqli->prepare("INSERT INTO `lunar_casino`.`posts` (`id`, `by`, `title`, `message`, `image`, `category`, …Run Code Online (Sandbox Code Playgroud) 如何使用php将多个数据插入mysql数据库.我尝试使用for循环,但没有运气.
//array of input boxes
$id1=array($aa1,$aa2,$aa3,$aa4,$aa5,$aa6,$aa7);
$timeRank1=array($a3,$a6,$a9,$a12,$a15,$a18,$a21);
for ($i = 0; $i < 7; $i++) {
require_once("connection.php");
$a = $id1[$i];
$b = $timeRank1[$i];
$sql = "INSERT INTO results (id,swim_rank)
VALUES ('".$a."','".$b."')";
Run Code Online (Sandbox Code Playgroud) 说我这样做:
$string = 'some string with a {$var}';
// Set var after
$var = 'variable'
// String with just set var
$newString = 'Here is my string: ' . $string;
echo $newString;
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我如何输出:
Here is my string: some string with a variable
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我可以用str_replace做到这一点,但我想知道是否有更简单的方法?
我有这个错误,我似乎无法找到正确的答案.我用PHP编写它但在调试后我试图直接在phpMyAdmin上编写它.这是我的SQL查询:
INSERT INTO users ( 'fName' , 'lName' , 'pCity' , 'cue' , 'email' , 'pass' , 'bDate' ) VALUES ('Me', 'You', 'Sofia', 'adf', '***', '***', '02/02/2010')
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这是我得到的错误:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''fName' , 'lName' , 'pCity' , 'cue' , 'email' , 'pass' , 'bDate' ) VALUES ('Kali' at line 1
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我在服务器上运行相应的PHP脚本时遇到同样的错误.我出错的任何想法?
是否可以使用内联代码(即在数组声明中)连接数组?例如:
function get_array() {
return array('four' => 4, 'five' => 5);
}
$arr = array(
'one' => 1,
'two' => 2,
'three' => 3,
get_array()
);
var_dump($arr);
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将导致:
Array(
[one] => 1
[two] => 2
[three] => 3
[0] => Array(
[four] => 4
[five] => 5
)
)
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而期望的结果将是:
Array(
[one] => 1
[two] => 2
[three] => 3
[four] => 4
[five] => 5
)
Run Code Online (Sandbox Code Playgroud) 我正在制作一个约会脚本,从数据库开始和关闭时间,然后显示开始和结束时间之间的时间来预订会议,每次会议只能预订半小时,所以我需要显示这样的时间使用单选按钮
9:00am - 9:30am
9:30am - 10:00am
10:00am - 10:30am
...
...
...
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我能够计算办公室开放的总小时数,并且使用for循环我能够显示时间
$office_start_time = '09:00:00';
$office_end_time = '16:00:00';
$start = explode(':', $office_start_time);
$end = explode(':', $office_end_time);
$total_hours = $end[0] - $start[0] - ($end[1] < $start[1]);
echo 'total hours: '.$total_hours;
echo '<br>';
//exit;
?>
<table class="table table-hover table-bordered">
<tbody>
<?php for ($i = 0; $i < $total_hours; $i++) {
echo "<input name='time' type='radio' value='09:00|09:30'> 9:00am-9:30am<br/>";
?>
<?php } ?>
</tbody>
</table>
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我的问题是上面的代码给了我一个像下面的输出,我坚持如何获得正确的结果

如果我能得到一些关于如下显示时间的帮助,我将非常感激
9:00am - 9:30am
9:30am - 10:00am …Run Code Online (Sandbox Code Playgroud) 如何删除字符串中的“-” ?
$text = 'lorem ipsum - dolor sit amet!';
$lorem = strstr($text, '-');
echo $lorem;
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返回:
- 多洛坐阿梅特!
我需要这个:
多洛坐阿梅特!
我正在研究我的PHP脚本来解析html网页.我正在使用file_get_contents打开网址来获取内容列表.
这是代码:
$links = $row['links'];
$result = file_get_contents($links);
$html_content = str_replace("<a id='rowTitle1' class", "<a id='rowTitle1' class",$result);
print $html_content;
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这是html输出:
<li class="zc-ssl-pg" id="row1-1" style="">
<span id="row1Time" class="zc-ssl-pg-time">6:00 PM</span>
<a id="rowTitle1" class="zc-ssl-pg-title" href='http://www.mysite.com'>The Middle</a>
<a class="zc-ssl-pg-ep" href='http://www.mysite.com'>"Thanksgiving IV"</a>
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你能告诉我如何使用file_get_contents从row1-1类中的row1Time,rowTitle1和zc-ssl-pg-ep标签中获取值吗?
它相当于MySQL to_days()函数.
是否有内置PHP函数可以执行此操作,还是需要将某些内容拼凑在一起?