小编Jus*_*ime的帖子

我确信这对jQuery专家来说很简单,但我是一个后端人,并且找不到最好的方法来做到这一点.我在Drupal中有两个数组,一个是视图名称列表,另一个是包含每个视图的显示列表的数组.这是填充两个数组的代码:

 //load list of views in to array for select lists
$views = views_get_all_views();
$viewnames = array();
$viewdisplays = array();
foreach ($views as $view) {
  $viewnames[$view->name] = $view->name; 
  foreach ($view->display as $k) {
    $id = $k->id;
    $title = $k->display_title;
    $viewdisplays[$view->name]['id'] = $id;
    $viewdisplays[$view->name]['title'] = $title;
  }
}

这是我正在使用的表单的片段:

$form['view'] = array(
  '#type' => 'select',
  '#title' => t('Select the view to be used for display'),
  '#options' => $viewnames,
);
$form['view_display'] = array(
  '#type' => 'select',
  '#title' => t('Select the display of …