小编pse*_*udo的帖子

我有3个不同的对象A,B和C.根据给定的参数,我想在这些不同的对象中进行选择.在编程中,

class A { 
  public: 
    void printHello() { cout << "HELLO A" << endl; }
}; 

class B { 
  public: 
    void printHello() { cout << "HELLO B" << endl; }  
};

class C { 
   public: 
     void printHello() { cout << "HELLO C" << endl; }  
}; 

int main () { 
    string key = "c"; 
    A a; 
    B b; 
    C c; 
    Object obj; // I don't know how to declare Object. 

    if (key == "a") …

我有一个A像这样的python类.

class A: 
   def __init__(self, name): 
       self.name = name

   def print_lastname(self, lastname): 
       print(lastname)

我必须像这样调用这个代码.

import B
a = B.A("hello")
a.print_lastname("John")

目前,我需要A从我的C++代码中使用这个类.我到目前为止.

Py_Initialize(); 
string hello = "hello"; 
PyObject *module, *attr, *arg; 
module = PyObject_ImportModule("B"); // import B
attr = PyObject_GetAttrString(module, "A"); // get A from B
arg = PyString_FromString(hello.c_str()); 
instance = PyInstance_New(attr, arg, NULL); // trying to get instance of A with parameter "hello"
Py_Finalize(); 

但我收到了错误

异常TypeError:来自'/usr/lib64/python2.7/threading.pyc'的模块'threading'中的'参数列表必须是元组'

如何从C import语句到a.print_name("John")C++实现？任何帮助表示赞赏.

我正在尝试使用模板动态设置struct中的字段.我在代码中写了两种方法.这两种方法都不起作用说no member named t.age.我怎么能动态设置字段？任何帮助表示赞赏.

#include <iostream> 

using namespace std; 

struct hello { 
    string name; 
}; 

struct bye { 
    int age; 
}; 

template <typename T>  
void printHello(string key) { 
    T t;  
    if (key == "HELLO") { 
        t.name = "John"; 
    }   
    else { 
        t.age = 0;  
    }   
} 

template <typename T>
T setStruct(T t) {   
    if (typeid(t) == typeid(hello)) {
        t.name = "John";
    } 
    else {
        t.age = 0;
    }
    return t; 
}

int main() { 
    //printHello<hello>("HELLO"); // ERROR: no …