小编dan*_*xon的帖子

我有2个具有相同功能的按钮，即从API获取数据，然后转换为html，然后使用jQuery将其附加到<div>。最后，使用漂亮的 jQuery插件显示它以将HTML元素显示为滑块。

但是，单击第一个按钮后，如果我单击第二个按钮（反之亦然），则slick（滑块）将不再起作用。

该的Javascript代码：

$(document).ready(function(){

    /*
    Description  : Handle Day Button Event
    */
    $('.dayList').on("click", function(event)
    {
            var dayChild = $(this).attr('id');

            //::refresh day lline
            $('.hour-to-hour-line').empty();    
            getHourList(dayChild,function()
            {

                /* 
                The Slick
                */
                $('.hour-to-hour-line').slick({
                  dots: false,
                  infinite: false,
                  speed: 1000,
                  slidesToShow: 6,
                  slidesToScroll: 1,
                  focusOnSelect: true,
                  arrows: false,
                  slickSetOption: true
                }); 
          });   
    });
});

该HTML代码：

<div id="monday" class="dayList" data-daycount = "1" tabindex="1"> Monday </div>
<div id="tuesday" class="dayList" data-daycount …

钢笔就在这里

当根据两个元素的类的存在点击链接/按钮时,我有两个元素设置来改变宽度,增加或减少.只有if一节if...else中的.toggle功能似乎是工作.抽屉打开但随后在触发元素的后续点击时不会关闭,尽管通过单击触发元素仍然可以成功地来回更改类.

我在这里错过了什么？谢谢.

javascript与jquery

    var container = document.getElementById('container');

    container.widthOpen = '800px';
    container.widthClosed = '210px';

    container.isOpen = function() {
      return this.classList.contains('open');
    };

    container.toggle = function() {
      this.classList.toggle('open');
      if (this.isOpen) {
        $(this).animate({
          width: container.widthOpen
        });
      } else {
        $(this).animate({
          width: container.widthClosed
        });
      }
    };

    var drawer = document.getElementById('drawer');

    drawer.widthOpen = '600px';
    drawer.widthClosed = '10px';

    drawer.isOpen = function() {
      return this.classList.contains('open');
    };

    drawer.toggle = function() {
      this.classList.toggle('open');
      if (this.isOpen) {
        $(this).animate({
          width: drawer.widthOpen
        });
      } else …

public class RunProg {
    static int input1; //for creating new human;
    static boolean Married; //for knowing if married or not
    static String isMarried; //for the YES or No of Married Boolean

public static void main(String[] args) {


    Scanner input = new Scanner(System.in);


    System.out.print("What would you like to do? \n 1-Create new Human?\n");
    input1 = input.nextInt();
    input.nextLine();

    //Inputs for The NEW HUMAN
    if (input1 == 1) {
        System.out.println("Enter name:");
        String Name = input.nextLine();

        System.out.println("Good! Now enter the age of " + …