小编moo*_*eek的帖子

如果最初我有一个日期字符串,如何在PHP中找到一周中最近的一天07.05.2010？例如,我想找到最近的星期日(或一周中的任何一天).我该如何实现呢？谢谢

我有一个动态填充(由ajax)选择框,其结果选项如下:

<select id="destination" name="destination">
<option value="london-paris">London-Paris</option>
<option value="paris-london">Paris-London</option>

<option value="london-newyork">London-New-York</option>
<option value="newyork-london">New-York-London</option>

<option value="london-berlin">London-Berlin</option>
<option value="berlin-london">Berlin-London</option>

<option value="london-helsinki">London-Helsinki</option>
<option value="helsinki-london">Helsinki-London</option>

......实际上有更多但不是本质

我想要的是在加载列表后使用Javascript(可能使用Jquery或Mootools)对optgroup的每个这两个选项部分进行分组,这样在每个组之前 - 我们添加一个带有我们从第二个选项获得的标签的optgroup标签该组的html(实际上是破折号之前的单词):

<select id="destination" name="destination">
<optgroup label="Paris">
<option value="london-paris">London-Paris</option>
<option value="paris-london">Paris-London</option>
</optgroup>
<optgroup label="New-York">
<option value="london-newyork">London-New-York</option>
<option value="newyork-london">New-York-London</option>
</optgroup>
<optgroup label="Berlin">
<option value="london-berlin">London-Berlin</option>
<option value="berlin-london">Berlin-London</option>
</optgroup>
<optgroup label="Helsinki">
<option value="london-helsinki">London-Helsinki</option>
<option value="helsinki-london">Helsinki-London</option>
</optgroup>
</select>

但是,每组中总有两个目的地.

请提前告知如何实施此建议.

我有一个$_SESSION["animals"]包含深度json对象的会话变量,其值为:

$_SESSION["animals"]='{
"0":{"kind":"mammal","name":"Pussy the Cat","weight":"12kg","age":"5"},
"1":{"kind":"mammal","name":"Roxy the Dog","weight":"25kg","age":"8"},
"2":{"kind":"fish","name":"Piranha the Fish","weight":"1kg","age":"1"},
"3":{"kind":"bird","name":"Einstein the Parrot","weight":"0.5kg","age":"4"}
}'; 

例如,我想找到"Piranha the Fish"的行,然后将其删除(并将json_encode重新编码).这该怎么做？我想我需要在json_decode($_SESSION["animals"],true)结果数组中搜索并找到要移除的父键但是我仍然被卡住了.

我正在调查Zend Framework并且目前正在计算结果的sql查询行...我尝试的每个方法(来自文档和一些博客和教程)都会返回错误(如Call to undefined function)或者只是给出不正确的值.

我试过这个:

$checkquery = $db->select()
   ->from('users', 'COUNT(*)')
   ->where('login = ?', $login)
   ->where('password = ?', $password)
   ->query();

$checkrequest=fetchRow($checkquery)->num;

......然后这个:

$checkquery = $db->select()
   ->from('users', '*')
   ->where('login = ?', $login)
   ->where('password = ?', $password)
   ->query();

$checkrequest=count($checkquery->fetchAll());

乃至:

$checkquery = $db->select()
   ->from('users', '*')
   ->where('login = ?', $login)
   ->where('password = ?', $password)
   ->query();

$checkrequest=$checkquery->fetchAll()->num;

还rowCount()和count(fetchRow())和count(fetchAll()->toArray()).但总是在进一步插入函数中我在db中收到错误消息或重复插入.那么在Zend Framework 1.9中使用select子句进行结果行计算的正确方法是什么(我使用这个)？

使用 Swift 3 我正在我的应用程序中实现 Apple Pay，并尝试将我收到的 PKPaymentToken 发送paymentAuthorizationViewController到银行的 API 以处理付款，但没有成功。我发送的数据总是被拒绝。

银行支持建议我发送整个payment.token而不是，payment.token.PaymentData但我不知道该怎么做，原因payment.token是PKPaymentToken的实例我所知无法转换为字符串或编码为 base64。

   func paymentAuthorizationViewController(_ controller: PKPaymentAuthorizationViewController, didAuthorizePayment payment: PKPayment, completion: @escaping ((PKPaymentAuthorizationStatus) -> Void)) {
        self.processPayment(payment: payment, completion: completion)
    }

    func processPayment(payment: PKPayment, completion: @escaping ((PKPaymentAuthorizationStatus) -> Void)) {

        print("Payment token: \(payment.token)")

        let paymentData=String(data: payment.token.paymentData.base64EncodedData(), encoding: .utf8)

        var request = URLRequest(url: URL(string: "https://bankapi.com/method")!)
        request.httpMethod = "POST"
        let postString = "orderid=\(orderid)&token=\(String(describing: paymentData))&amount=\(price)"
        print("POST: \(postString)")
        request.httpBody = postString.data(using: .utf8)

        let …