小编Jay*_*oli的帖子

我有一个UITableViewController,它带有一个选项列表.在用户点击一个之后,我想返回上一个视图.使用我正在使用的代码,返回似乎太快了.我想暂停0.2秒左右,让用户有时间查看他们的选择.这是我现在使用的代码:

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath {
    NSUInteger oldSelection = [[selectedCriteria objectAtIndex:criteriaSection] integerValue];

    [tableView deselectRowAtIndexPath:indexPath animated:YES];
    // Since there's a "none" selection, we don't deselect if the user taps the one that's already selected
    if ([indexPath row] != oldSelection + 1) {
        NSIndexPath *selectionIndexPath = [NSIndexPath indexPathForRow:oldSelection+1 // Shift down for "None"
                                                inSection:[indexPath section]];
        UITableViewCell *checkedCell = [tableView cellForRowAtIndexPath:selectionIndexPath];
        [checkedCell setAccessoryType:UITableViewCellAccessoryNone];

        [[tableView cellForRowAtIndexPath:indexPath] setAccessoryType:UITableViewCellAccessoryCheckmark];
        [selectedCriteria replaceObjectAtIndex:criteriaSection
                                    withObject:[NSNumber numberWithUnsignedInteger:[indexPath row]-1]];     
    }

    [[self navigationController] popViewControllerAnimated:YES];
}

是否有一种在弹出视图控制器之前添加短延迟的好方法？