小编And*_*Dog的帖子

我想创建一个多语言网站,但我不希望语​​言出现在URI中,例如example.com/fr/about(我不想这样).我只是想改变文字语言.我的问题是,我所做的第一种加载语言是永远的.为什么？如果我做:

$this->config->set_item(‘language’,‘english’);
$this->lang->load(‘messages’);
$this->config->set_item(‘language’,‘french’);
$this->lang->load(‘messages’);

要么

$this->lang->load(‘messages’,‘english’);
$this->lang->load(‘messages’,‘french’);

只是英文出现了.我怎样才能解决这个问题？

我的配置语言自动加载是空的.

谢谢您的帮助.

我快到了!!在我的mac OSX中部署EveryBlock的ebcode - 这是我的settings.py:

http://pastebin.com/ndQ57LCH

这是整个错误:

  Traceback (most recent call last):
  File "/Library/Python/2.6/site-packages/django/core/servers/basehttp.py", line 280, in run
    self.result = application(self.environ, self.start_response)
  File "/Library/Python/2.6/site-packages/django/core/servers/basehttp.py", line 674, in __call__
    return self.application(environ, start_response)
  File "/Library/Python/2.6/site-packages/django/core/handlers/wsgi.py", line 234, in __call__
    signals.request_started.send(sender=self.__class__)
  File "/Library/Python/2.6/site-packages/django/dispatch/dispatcher.py", line 172, in send
    response = receiver(signal=self, sender=sender, **named)
  File "/Library/Python/2.6/site-packages/django/db/__init__.py", line 90, in reset_queries
    for conn in connections.all():
  File "/Library/Python/2.6/site-packages/django/db/utils.py", line 101, in all
    return [self[alias] for alias in self]
  File "/Library/Python/2.6/site-packages/django/db/utils.py", line 93, in __getitem__
    conn = backend.DatabaseWrapper(db, alias) …

我有以下测试代码.

a = ['a', 'b', 'c', 'd', 'e']
c = a * 3
b = a

但b in c返回False.b是c的子序列,列表c包含b.那为什么它会返回虚假？

提前致谢.

我正在为Rhodes移动应用程序框架学习Ruby 并遇到了这个问题:Rhodes的HTTP客户端将JSON响应解析为Ruby数据结构,例如

puts @params # prints {"body"=>{"results"=>[]}}

由于键"body"在这里是一个字符串,我的第一次尝试@params[:body]失败了(是nil),而它必须是@params['body'].我发现这是最不幸的.

有人可以解释为什么字符串和符号有不同的哈希值,即:body.hash != 'body'.hash在这种情况下？