小编Pen*_*m10的帖子

我是jQuery的新手,有人可以解释这段代码的作用:

$("#currency form").submit(function(e) {

        triggers.eq(1).overlay().close();
        return e.preventDefault();
    });

我有以下设置,空视图文本没有显示...

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
            getListView().setEmptyView(findViewById(R.id.empty));
    getListView().setTextFilterEnabled(true);

    setListAdapter(null);// to have empty list
}

布局文件是:

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout android:id="@+id/myScrollLayout"
    android:layout_width="fill_parent" android:layout_height="fill_parent"
    android:orientation="vertical" xmlns:android="http://schemas.android.com/apk/res/android">
    <FrameLayout android:layout_width="fill_parent"
        android:layout_height="0dip" android:layout_weight="1">
        <ListView android:id="@android:id/list" android:layout_width="fill_parent"
            android:layout_height="fill_parent" android:drawSelectorOnTop="false" />

        <!-- Here is the view to show if the list is emtpy -->
        <ScrollView
            android:id="@android:id/empty" android:layout_width="fill_parent"
            android:layout_height="fill_parent">
            <TextView android:id="@+id/emptyText" android:layout_width="fill_parent"
                android:layout_height="fill_parent" android:text="@string/contact_empty_help"
                android:textSize="20sp" android:textColor="?android:attr/textColorSecondary"
                android:paddingLeft="10dip" android:paddingRight="10dip"
                android:paddingTop="10dip" android:lineSpacingMultiplier="0.92" />
        </ScrollView>
    </FrameLayout>
</LinearLayout>

字符串定义为:

<string name="contact_empty_help">"You don't have any contacts to display.\n\nTo add contacts, you have …

当我调试我的应用程序突然出现此错误时.我该如何处理这种错误？

我不知道在哪里以及如何造成.

Daemon System Thread [<5> HeapWorker] (Suspended (exception IllegalStateException)) 
    SQLiteCursor.finalize() line: 603   
    NativeStart.run() line: not available [native method]   

拿这些例子

Smith John
Smith-Crane John
Smith-Crane John-Henry
Smith-Crane John Henry

我希望得到John 空格后面的第一个单词,但它可能直到最后,它可能直到非字母字符.这将如何在Java 1.5中？

我一直在尝试使用Scala开发Android应用程序.

我已经到了可以让应用程序编译的地步,但是没有帮助函数,例如:

button.setOnClickListener( () => {
    text.setText("test")
})

(我在说那里的关闭)

我看到很多对scala-android.jar的引用,并且在我的项目中有这个文件,但我不确定它是做什么的,或者如何使用它.我觉得它有这些辅助转换功能,但我不确定.jar -tvf scala-android.jar在文件上运行给我这个:

401 Sun Jun 06 10:06:02 MDT 2010 scala/Function0$class.class
431 Sun Jun 06 10:06:02 MDT 2010 scala/Function0.class
572 Sun Jun 06 10:06:02 MDT 2010 scala/Function1.class
282 Sun Jun 06 10:06:02 MDT 2010 scala/ScalaObject$class.class
271 Sun Jun 06 10:06:02 MDT 2010 scala/ScalaObject.class
458 Sun Jun 06 10:06:02 MDT 2010 scala/runtime/BoxedUnit.class

如果这不是我想要的,是否有一个简单的库可以为这种东西进行转换？

在此代码中,我请求GPS的位置更新

locMan.requestLocationUpdates(LocationManager.GPS_PROVIDER,20000, 1, gpsListener);

但是我怎样才能确保它也能收听Wifi或Cell ID更新呢？

以下查询花费太多时间,很可能是因为"不在"使用.

你能建议改进吗？

SELECT vcode, 
       vname, 
       1014 AS fid 
FROM   testcodes co 
WHERE  co.vcode NOT IN (SELECT dict.vcode 
                        FROM   datadictionary dict 
                        WHERE  dict.fid = 1014) 

关于结构的一件事是.vCode,vName是varchar,testCodes和DataDictionary具有相同的结构.

我搜索了这个问题,发现左连接可以解决这个问题？(为什么它做得更好,如何做到)？

有人可以指导它是否可以改进???

我正在尝试上传一个包含多个嵌套级别的测试数据表,但我似乎无法获得指定模式的语法.

这是我目前的架构文件:

{
  "name":"city", "type":"RECORD",
    [
      {"name":"id", "type":"INTEGER"},
      {"name":"name", "type":"STRING"},
      {"name":"country", "type":"STRING"},
      {"name":"coord", "type":"RECORD"},
        [
          {"name":"lon", "type":"FLOAT"},
          {"name":"lat", "type":"FLOAT"}
        ],
    {"name":"time", "type":"TIMESTAMP"}
  ]
}

以下是数据示例:

{"city":{"id":1283240,"name":"Kathmandu","country":"NP","coord":{"lon":85.316666,"lat":27.716667}},"time":1394865171,"data":[{"dt":1394852400,"main":{"temp":296.15,"temp_min":293.866,"temp_max":296.15}},{"dt":1394863200,"main":{"temp":301.51,"temp_min":299.345,"temp_max":301.51}}]}

在完整文件中,我有多个城市,每个城市每天都有多个"数据"点.

谢谢

标记

我有这个问题:

SELECT campaign.id AS campaign_id,
       GROUP_CONCAT(utm.campaign) AS utm_campaign
FROM [email_event]
WHERE (TIMESTAMP BETWEEN SEC_TO_TIMESTAMP(1412136000) AND SEC_TO_TIMESTAMP(1414814340))
GROUP BY campaign_id;

我希望运行一个独特的GROUP_CONCAT,因为现在在输出中重复相同的条目.

UPDATE

我已将您的解决方案扩展到此:

SELECT campaign.id AS campaign_id,
       GROUP_CONCAT(utm.campaign) AS utm_campaign,
       GROUP_CONCAT(utm.content) AS utm_content
FROM
  (SELECT *
   FROM
     (SELECT 507 AS campaign.id,
             'remarketingemail' AS utm.campaign,
             'newsletter_feb' AS utm.content),
     (SELECT 508 AS campaign.id,
             'remarketingemail' AS utm.campaign,
             'newsletter_jan' AS utm.content),
     (SELECT 508 AS campaign.id,
             'remarketingemail' AS utm.campaign,
             'newsletter_feb' AS utm.content),
     (SELECT 508 AS campaign.id,
             'adwordscamp' AS utm.campaign,
             'cyber_monday' AS utm.content) )
GROUP BY campaign_id; …

我想实现类似的东西

select * from table1
where not exists (select 1 from table2 where
                  table1.col1 = table2.col1 and table1.col2 = table2.col2)

我无法在 BQ 中实现这一点。对于完成这项工作的任何帮助，我们将不胜感激。